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dsp73
3 years ago
10

Please help me, on small sentence.

Mathematics
1 answer:
enot [183]3 years ago
5 0

Answer:

no tengo ningún drama

Step-by-step explanation:

i dont have any drama !!!

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What is the solution to the inequality?
Lilit [14]
The answer would be x>-3
6 0
3 years ago
it costs $2 to spin the spinner shown below. if you land on an even number, you win $10. if you land on an odd number, you get $
Svetlanka [38]

Answer:

$1

Step-by-step explanation:

because there is more odd numbers then even

4 0
3 years ago
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Blood is a buffer solution. When carbon dioxide is absorbed into the bloodstream, it produces carbonic acid and lowers the pH. T
Irina18 [472]

Answer:

x ≅ 20.10 torr

Step-by-step explanation:

Given that the equation which models blood pH in the question is;

pH(x)=6.1+log(800/x)

where;

pH = 7.7

x = partial pressure of carbon dioxide in arterial blood, measured in torr.

we are asked to find (x)

In order to do that, we use the given equation:

pH(x)=6.1+log(800/x)

since pH = 7.7

7.7 = 6.1 + log (800/x)

7.7 - 6.1 =  log (800/x)

1.6 =  log (800/x)

10^{1.6}= \frac{800}{x}

x= \frac{800}{10^{1.6}}

x = 20.09509145

x ≅ 20.10 torr

4 0
3 years ago
Is this a piecewise graph function? Check using vertical line test. <br> HELP!
IRINA_888 [86]
The answer is- Yes, the piecewise graph is a function because it passes the vertical line test.


Hope that helped!!!
8 0
3 years ago
Solve for x : log(3x) + log(x + 4) = log(15).<br><br>Please explain it to me.​
zlopas [31]

Answer:

x = 1

Explanation:

\sf \rightarrow log(3x) + log(x + 4) = log(15)

Rule: log(a) + log(b) = log(ab)

\sf \rightarrow log(3x(x + 4)) =  log(15)

cancel out log on both sides

\sf \rightarrow 3x(x + 4) = 15

relocate constant variable

\sf \rightarrow 3x^2 + 12x -15 = 0

take 3 as a common factor

\sf \rightarrow 3(x^2 + 4x -5) = 0

divide both sides by 3

\sf \rightarrow x^2 + 4x -5 = 0

middle term split

\sf \rightarrow x^2 + 5x -x-5 = 0

factor common terms

\sf \rightarrow x(x  + 5) -1(x+5)= 0

collect into groups

\sf \rightarrow (x-1)(x+5)= 0

set to zero

\sf \rightarrow x-1 = 0 , \ x+5= 0

relocate variables

\sf \rightarrow x = 1,  \ x = -5

There must be a positive solution for log, so the solution is only x = 1

3 0
2 years ago
Read 2 more answers
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