X^4=256
x^4-256=0
(x^2)^2-(16)^2=0
(x^2+16)(x^2-16)=0
either x^2+16=0
it gives complex roots.
or x^2-16=0
or x^2-4^2=0
(x+4)(x-4)=0
either x+4=0,x=-4
or x-4=0
x=4
F ( x ) = ( 3 x + 6 ) ( 3 x - 6 ) / ( 3 x + 6 ) = 3 x - 6
and for domain : 3 x + 6 ≠ 0
3 x ≠ - 6
x ≠ - 2
anwser graph of 3 x - 6, with discontinuity at - 2
It’s 3, absolute value makes everything positive
Answer:
Peter's number is 36.
Step-by-step explanation:
If you subtratct 13 from 36, you get 23.
If you multiply that times -3, you get -69.
(The way I got 23 was by dividing -69 and -3)
I hope this helped you even though it's late.
