Answer:
And the 68% confidence interval is given by (91.1186, 97.2814)
Step-by-step explanation:
For this case we know that mean time that visitors stay at a museum is given by:
The standard deviation is given by:
And the standard error is given by:
And we want to interval captures 68% of the means for random samples of 25 scores and for this case the critical value can be founded like this using the normal standard distribution or excel:
We can find the interval like this:
And replacing we got:
And the 68% confidence interval is given by (91.1186, 97.2814)
So, We Have A Rate That We Need To Simplify. We Have:
88 students for every 4 classes
So, We Need To Simplify This Rate. In Order To Do This, We Need To Change Is To A Fraction. It Is:
88 students
---------------
4 classes
Now, We Have To Simplify. We Can Do That By Remembering How To Simplify Fractions.
So,
88 ÷ 2 = 44 ÷ 2 = 22 students
--- --- ---------------
4 ÷ 2 = 2 ÷ 2 = 1
So, The Unit Rate For 88 Students For 4 Classes Is:
22 Students For One Class
Answer:
82 cm
Step-by-step explanation:
In rectangles diagonals are equal and bisect each other
AO = BO
5x + 1 = 4x + 9
Subtract 1 from both sides
5x = 4x + 9 -1
5x = 4x + 8
Subtract 4x from both the sides
5x - 4x = 8
x = 8
AO = 5x + 1
= 5*8 +1
= 40 + 1
AO= 41 cm
Diagonal = 2*41 = 82 cm
Answer:
No, some of the ordered pair in this graph have the same first element.
Step-by-step explanation:
The relation of a function is that it expresses a dependence of one element on another. There is a one to one relation, which means that one point can not be used more then once.
Some ordered pairs in this graph have the same first element and are used more then once. So this graph can not represent a function.
Answer:
The combination 9 mm, 6mm, 5mm will not form a triangle.
9 +6 = 15 > 5
6+5= 11 < 9
9+5 =14 > 6
Explanation :
because the side length of triangle does not obey triangle inequality theorem.
The triangle inequality theorem:
The sum of the lengths of any two sides of a triangle is greater than the length of the third side.
