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son4ous [18]
2 years ago
14

Your best friend is really struggling with their math class. You passed the same class last term with an A, so you’ve been helpi

ng them do practice problems and double-checking their homework. The professor has given them a take-home exam for their mid-term, and they want your help completing the exam. Is this an academic integrity violation? Why or why not? How would you handle this situation, and why would you handle it in that way?
Mathematics
1 answer:
ra1l [238]2 years ago
3 0

Answer:

no

Step-by-step explanation:

you have done your part by helping in their study session,if you help them cheat you will suffer the consequences if he/she is caught,

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Find the value for x and y for the triangle. Show work.
HACTEHA [7]

Answer:x= 8/√3, y= 16/ √3

Step-by-step explanation:

See the picture below

4 0
3 years ago
Please help me out ! I don't understand how to get this
Scilla [17]

The value of angle x is 53° for the given triangle.

<h3>What is angle?</h3>

An angle is the formed when two straight lines meet at one point, it is denoted by θ.

In the given isosceles triangle,

one angle is 74°,

Since, two sides of the isosceles triangle are equal, so the corresponding angles will be equal to x.

The sum of angles of a triangle = 180°

x + x + 74 = 180

2x = 106

x = 53

The required value of angle x is 53°.

To learn more about Angle on:

brainly.com/question/28451077

#SPJ1

6 0
1 year ago
Given: △ABC, BC&gt;AC, D∈ AC , CD=CB Prove: m∠ABD is acute
Aleksandr [31]

Answer:

Step-by-step explanation:

Given: △ABC, BC>AC, D∈ AC , CD=CB

To prove: m∠ABD is acute

Proof: In ΔABC, the angle opposite to side BC is ∠BAC and  the angle opposite to side  AC is ∠ABC.

Now, it is given that  BC>AC, then ∠BAC>∠ABC..                       (1)

In ΔBDC, using the exterior angle property,

∠ADB=∠DBC+∠BCD

∠ADB=∠DBC+∠BCA

⇒∠ADB>∠BAC                            (2)

From equation (1) and (2), we get

∠ADB>∠BAC

⇒∠ADB>∠ABC

⇒DB>AB

Hence,    m∠ABD is acute            

4 0
3 years ago
Use the substitution u = tan(x) to evaluate the following. int_0^(pi/6) (text(tan) ^2 x text( sec) ^4 x) text( ) dx
Rudiy27
If we use the substitution u = \tan x, then du = \sec^2 {x}\ dx. If you try substituting just u and du into the integrand, though, you'll notice that there's a \sec^2x left over that we have to deal with.

To get rid of this problem, use the identity \tan^2 x + 1 = \sec^2 x and substitute in the left side of the identity for the extra \sec^2x, as shown:

\int\limits^{\pi/6}_0 {tan^2 x \ sec^4 x} \, dx
\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx

From there, we can substitute in u and du, and then evaluate:

\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx
\int\limits^{\frac{1}{\sqrt{3}}}_0 {u^2(u^2 + 1)} \, du
\int\limits^{\frac{1}{\sqrt{3}}}_0 {u^4 + u^2} \, du
= \left.\frac{u^5}{5} + \frac{u^3}{3}\right|_0^\frac{1}{\sqrt{3}}
= (\frac{(\frac{1}{\sqrt{3}})^5}{5} + \frac{(\frac{1}{\sqrt{3}})^3}{3}) - (\frac{(0)^5}{5} + \frac{(0)^3}{3})
= \frac{1}{45\sqrt{3}} + \frac{1}{9\sqrt{3}} = \frac{6}{45\sqrt{3}} = \bf \frac{2}{15\sqrt{3}}


8 0
3 years ago
Which expressions are equivalent to the one below? Check all that apply log₂ 2 + log₂ 8
S_A_V [24]

Answer:

A. 4 B.  log₂(2^4)

Step-by-step explanation:

A. log₂ 2 = log₂ 2¹ = 1

log₂ 8 = log₂ 2³ = 3

log₂ 2 + log₂ 8 = 1 + 3 = 4

B. *log₂ 2⁴ = 4

3 0
3 years ago
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