It's not commutative:
<em>a</em> * <em>b</em> = 3<em>a</em> + 2<em>b</em>
but
<em>b</em> * <em>a</em> = 3<em>b</em> + 2<em>a</em>
We have equality only for
3<em>a</em> + 2<em>b</em> = 3<em>b</em> + 2<em>a</em> → <em>a</em> = <em>b</em>
Answer:
The graph of image and preimgae is shown below.
Step-by-step explanation:
From the given figure it is noticed that the vertices are A(-2,2), B(5,2), C(5,0), D(0,0), F(0,-2) and G(-2,-2).
It is given that figure ABCDFG is rotated by positive 90° about the origin (0,0).
Positive means counter clockwise and negative means clockwise.
If a figure is rotated by counter clockwise 90° about the origin (0,0), then
![(x,y)\rightarrow (-y,x)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Crightarrow%20%28-y%2Cx%29)
The vertices of image are
![A(-2,2)\rightarrow A'(-2,-2)](https://tex.z-dn.net/?f=A%28-2%2C2%29%5Crightarrow%20A%27%28-2%2C-2%29)
![B(5,2)\rightarrow B'(-2,5)](https://tex.z-dn.net/?f=B%285%2C2%29%5Crightarrow%20B%27%28-2%2C5%29)
![C(5,0)\rightarrow C'(0,5)](https://tex.z-dn.net/?f=C%285%2C0%29%5Crightarrow%20C%27%280%2C5%29)
![D(0,0)\rightarrow D'(0,0)](https://tex.z-dn.net/?f=D%280%2C0%29%5Crightarrow%20D%27%280%2C0%29)
![F(0,-2)\rightarrow F'(2,0)](https://tex.z-dn.net/?f=F%280%2C-2%29%5Crightarrow%20F%27%282%2C0%29)
![G(-2,-2)\rightarrow (2,-2)](https://tex.z-dn.net/?f=G%28-2%2C-2%29%5Crightarrow%20%282%2C-2%29)
The graph of image and preimgae is shown below.
Answer:
42.5 square units.
Step-by-step explanation:
This is a trapezoid.
The area of a trapezoid can be found by a+b/2(h)
a=12
b=5
h=5
Plug in.
5+12/2(5)
17/2(5)
8.5(5)
42.5
Answer:
3/215
Step-by-step explanation:
Integer numbers prime factorization
3 is a prime number, it cannot be broken down to other prime factors
215 = 5 × 43
Multiply all the common prime factors, by the lowest exponents.
But the two numbers have no common prime factors
gcf, hcf, gcd (3; 215) = 1