Una ambulancia se desplaza por la calle a 34 m/s emitiendo un estruendoso sonido de sirena a 304 Hz, Si usted se ALEJA de la amb
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<u>Answer:</u>
Takeoff speed of Kangaroo = 12.91 m/s
<u>Explanation:</u>
The distance reached by Kangaroo = 10 meter
Angle at which it jumps = 18°
The motion of Kangaroo is like a projectile, the distance traveled is the range of projectile.
Range of projectile = Time taken for the projectile to reach ground* Horizontal velocity
Time taken for the projectile to reach ground:
Time taken = Two times of the time taken for the projectile to reach maximum height
Time taken for the projectile to reach maximum height = Vertical speed / Acceleration = u sin θ/g
Time taken for the projectile to reach ground = 2 u sin θ/g
So Range of projectile =
We have Range = 10 meter, θ = 18⁰
Substituting
Takeoff speed of Kangaroo = 12.91 m/s
Answer:
R= 602 .11 N
Explanation:
The horizontal component of tension T will give reaction of the wall and the vertical component of T will balance the weight of of the climber .
T cos32 = R
710 x .848 = R
R= 602 .11 N .
