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Natali [406]
3 years ago
5

How fast must the space shuttle go to cover 20,000 meters in 4.0 seconds?

Physics
1 answer:
Advocard [28]3 years ago
7 0

Answer:

5000 m/s

Explanation:

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inna [77]
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Using the formula p=mv ...
Player A would have a momentum of 220 N•S
Player B would have a momentum of 0 because he is not moving

After the collision, the total momentum is still 220 N•S because energy is never lost, but now player A is at 0 and player B took his momentum. Think about it this way, if you bumped into something that wasn’t moving, it would fall and you most likely wouldn’t keep moving.

Elastic collisions are where the objects bounce each other and in inelastic collisions they stick together. I don’t watch much football but if you do this should make sense.
If the players fall down together (they tackle each other and fall? I think) it should be inelastic.

Sorry if this was long and confusing but I really hope this helps! ☺️
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<h3><u>Answer;</u></h3>

Mid-ocean ridges

<h3><u>Explanation</u>;</h3>
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From these examples, you can see a few things:

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4 0
3 years ago
Read 2 more answers
An electric dipole is formed from ±1.00nC charges spaced 3.00 mm apart. The dipole is at the origin, oriented along the x-axis.
Ronch [10]

Answer:

Value of electric field along the axis and equitorial axis  E=31.25\ N/c and E = 15.625\ N/c respectively.

Explanation:

Given :

Distance between charges , d = 3 \ mm =\dfrac{3}{1000}\ m=3\times 10^{-3}\ m.

Magnitude of charges , q=1\ nC = 10^{-9}\ C.

Dipole moment , p=qL=10^{-9}\times 3\times 10^{-3}=3\times 10^{-12} \ C\ m.

Case A) (x,y) = (12.0 cm, 0 cm) :

Electric field of dipole in its axis ,

E=\dfrac{2kp}{r^3}

Putting all values and r=12\times 10^{-2}\ m.

We get , E=31.25\ N/c.

Case B) (x,y) = (0 cm, 12.0 cm) :

Electric field of dipole on equitorial axis ,

E = \dfrac{kp}{r^3}

Putting all values and r=12\times 10^{-2}\ m.

We get , E = 15.625\ N/c.

Hence , this is the required solution.

7 0
3 years ago
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