Answer:
When a neutral atom looses an electron to another neutral atom, two charged atoms are created.
Explanation:
On the off chance that one of the two unbiased particle looses an electron, it turns out to be emphatically (charge: +1), in light of the fact that the electron conveys a charge of - 1. Thus, the other atom which acknowledges the electron turns out to be adversely charged (charge: - 1). And in the end, we will have two charged atoms.
Answer: 0.313 rad/s
Explanation:
The equation that relates the velocity
and the angular velocity
in the uniform circular motion is:
(1)
Where
is the radius of the space station (with a diaeter of 200m) that describes the uniform circular motion.
Isolating
from (1):
(2)
On the other hand, we are told the “artificial gravity” produced by the cetripetal acceleration
is
, and is given by the following equation:
(3)
Isolating
:
(4)
(5)
Substitutinng (5) in (2):
(6)
This is the angular velocity that would produce an “artificial gravity” of 9
.
ThIs is the same type of problem
find out the time value
3 = 1/2*a*T^2
6/10 = t^2
t = 0.77 seconds
and the distance is given 5 m
thus speed ,= distance/time
speed = 5/0.77
= 6.45 m/s
Kinetic energy of the horse and rider = 1/2 (mass) (speed)²
At 4.0 m/s : KE = 1/2 (55kg) (4 m/s)² = 440 joules
At 6.0 m/s : KE = 1/2 (55kg) (6 m/s)² = 990 joules
She increased the kinetic energy of herself and her vehicle by 550 joules,
so she must have put at least that much work into it.
For the 5.0Kg block with the force of 15 Newton, the coefficient of static friction (μ) comes out to be 0.306. Applying the formula F = μmg.
Static friction acts on stationary body/body at rest. Let μ be the coefficient of static friction between the block and the horizontal floor.
Using the formula: F = μmg
Where,
F = Force , m= mass of the block and g = gravity.
and values of: m= 5.0Kg, F= 15.0N, g= 9.8m/s²
We can get: μ = F/(mg)
μ = 15/49
μ =0.306
Therefore, coefficient of static friction (μ) = 0.306.
To learn more about static friction visit the link- brainly.com/question/13680415
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