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velikii [3]
3 years ago
6

HELP!! Shelley creates a logo using two similar icicle triangle shown below what is the length of side s in centimeters

Mathematics
1 answer:
Lapatulllka [165]3 years ago
6 0

Answer:

s = 12cm

Step-by-step explanation:

Since these are similar triangles, in order to find a missing side, you have to find the constant of proportionality

14/8 = 21/s          >> cross multiply

14s = 168             >> divide both sides by 14 to get s alone

s = 12

<em />

<em>another way to find the answer......</em>

Step-by-step explanation:

You still have to find the constant of proportionality, it's just going to be a bit faster this way

14/8 = 1.75

21/1.75 = 12

s = 12

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Suppose a poll is taken that shows that 765 out of 1500 randomly​ selected, independent people believe the rich should pay more
Zanzabum

Answer:

z=\frac{0.51 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1500}}}=0.775  

p_v =P(z>0.775)=0.219  

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly higher than 0.5

Step-by-step explanation:

Data given and notation

n=1500 represent the random sample taken

X=765 represent the successes

\hat p=\frac{765}{1500}=0.51 estimated proportion of successes

p_o=0.5 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.5:  

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.51 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1500}}}=0.775  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>0.775)=0.219  

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly higher than 0.5

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3 years ago
8600*(1+0.05*120/365)
iren2701 [21]

Answer:

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3 0
3 years ago
Which shows two equivalent fractions?
Sergio [31]

Answer:

A

Step-by-step explanation:

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3 years ago
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Based on data from a car bumper sticker​ study, when a car is randomly​ selected, the number of bumper stickers and the correspo
Viktor [21]
<span> Does the given information describe a probability​ distribution? </span>

Yes

<span> Assuming that a probability distribution is​ described, find its mean and standard deviation. </span>

The mean is equal to 0.6. The standard deviation is equal to 1.5

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<span>The minimum usual value is 0.</span>

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7 0
3 years ago
Plzz help and give me answers i will mark u as a brainliest and 5.0 stars and thanks also plzz fast​
Firlakuza [10]

Step-by-step explanation:

mode= -3 (most common number)

only one; -1 on Sunday

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