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Nookie1986 [14]
4 years ago
10

Slope is -2 a y-intercept of 5

Mathematics
1 answer:
Maksim231197 [3]4 years ago
5 0

Answer:

Step-by-step explanation:

slope = -2 ;  y-intercept =  5

y =mx + c

y = -2x + 5

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Complete the point slope equation of the line through (-5, 7) and (-4, 0).​
IgorLugansk [536]

For this case we have that by definition, the point-slope equation of a line is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

We have two points:

(x_ {1}, y_ {1}): (- 5,7)\\(x_ {2}, y_ {2}): (- 4,0)

We found the slope:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} =  \frac {0-7} {- 4 - (- 5)} = \frac {-7} {-4 + 5} = \frac {-7} {1} = - 7

Thus, the equation is of the form:

y = -7x + b

We substitute one of the points and find "b":

0 = -7 (-4) + b\\0 = 28 + b\\b = -28

Finally, the equation is:

y = -7x-28

Answer:

y = -7x-28

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3 years ago
Distance between points (1,2) (4,3)
GREYUIT [131]

Answer:

3.1

Step-by-step explanation:

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3 years ago
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What is the greatest common factor of the number pair 6x and 9x
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Answer:

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Step-by-step explanation:

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3 years ago
The number of cars running a red light in a day, at a given intersection, possesses a distribution with a mean of 3.6 cars and a
Iteru [2.4K]

Answer:

X \sim N(3.6,5)  

Where \mu=3.6 and \sigma=5

Then we have:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

With the following parameters:

\mu_{\bar X}= 3.6

\sigma_{\bar X} = \frac{5}{\sqrt{100}}= 0.5

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the number of cars running a red light of a population, and for this case we know the distribution for X is given by:

X \sim N(3.6,5)  

Where \mu=3.6 and \sigma=5

Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

With the following parameters:

\mu_{\bar X}= 3.6

\sigma_{\bar X} = \frac{5}{\sqrt{100}}= 0.5

5 0
3 years ago
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