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krok68 [10]
3 years ago
13

1 Calculate:

Mathematics
1 answer:
3241004551 [841]3 years ago
5 0
(a)=940
(b)=1680
(c)=1950
(d)=4440
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What is the value of x when -25(x - 4) = -55(x - 10) ?
Free_Kalibri [48]

Simplify both sides of the equation

-25(x-4)=-55(x-10)

(-25)(x) + (-25)(-4)=(-55)(x) + (-55) (-10)

Distribute

-25x+100=-55x+550

Add 55x  to both sides

-25x+100+55x=-55x+550+55x

30x+100-100=550-100

subtract 100 from both sides

30x+100-100=550-100

30x=450

divide both sides by 30

30x/30=450/30

x= 15

The value of x is 15


I hope that's help you my friend !

5 0
3 years ago
Read 2 more answers
I need to find the parent function and compare and contrast the domain and range of the parent function.
denpristay [2]
The parent function is f(x) = x^3 with domain = all real numbers and range = all real numbers.

The given function is f(x) = x^3 - 2 with domain = all real numbers and range = all real numbers.
8 0
3 years ago
Determine the number of possible triangles, ABC, that can be formed given angle A = 30°, a = 4, and b = 6.
Sophie [7]

Answer:

Step-by-step explanation:

Alright, lets get started.

using Sine Law,

\frac{sinA}{a}=\frac{sinB}{b}

\frac{sin30}{4}=\frac{sinB}{6}

sinB=0.75

angle B = 48.6

Another angle will be

angle B' = 180-48.6 = 131.4

considering angle B, angle C = 180 - (48.6+30)=101.4

considering angle B', angle C' = 180-(131.4+30)=18.6

\frac{sinA}{a}=\frac{sinC}{c}

\frac{sin30}{4}=\frac{sin101.4}{c}

c = 7.84

Similarly, finding c'

\frac{sinA}{a}=\frac{sinC'}{c'}

\frac{sin30}{4}=\frac{sin18.6}{c'}

c'=2.55

Hence two triangles are possible with below details:  :   Answer

A = 30, B = 48.6, C = 101.4, c = 7.84

A = 30, B' = 131.4, C' = 18.6, c' = 2.55

Hope it will help :)

5 0
3 years ago
The rectangle has a length of (x+3) and the width (x+1)
Tamiku [17]
The answer is b
Because you have to add da x and dat is 2x den add da numbers which is 4
7 0
3 years ago
Which equation could he have solved? Is it A or B
Artist 52 [7]
A or B ....it’s your choice
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