1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula 
to find the distance from point 
to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer: 
.
Answer:
y = 1/2x + 2
Step-by-step explanation:
First you have to determine the slope which is the opposite reciprocal of the slope of the line given.
So we take the slope -2 and reciprocate and by flipping the numerator and denominator which makes it -1/2.
Then we have to make it the opposite, like making a negative into a positive or a positive into a negative. So that would make it positive 1/2.
We now have the slope which is 1/2 and not we have to make sure it goes through point (2,3).
To do that, we must adjust the y-intercept until it goes through that point. We result in getting the y-intercept of 2.
The answer is y = 1/2x + 2
Answer:
<u><em>note:</em></u>
<u><em>solution is attached due to error in mathematical equation. please find the attachment</em></u>
