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vovangra [49]
3 years ago
14

Help ....,?.?.??.?.?..?.?.?.?

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
4 0

Answer:

1

Step-by-step explanation:

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Solve the equation to find a positive value of c: 62 + 82 = c2
Artist 52 [7]
c^{2} = 144
c = ±\sqrt{144}
c = <span>±12</span>
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4 years ago
Read 2 more answers
Please answer this is so urgent
kolezko [41]
The answer is 4565 / 63


Sorry this might be to late...
8 0
3 years ago
Help please I need help
liberstina [14]

Answer:

15/8

Step-by-step explanation:

Opp/Adj of angle x means Tan x

that would be 15/8

5 0
3 years ago
An inhalation aerosol contains 225 mg of metaproterenol sulfate, which is sufficient for 300 inhalations. How many micrograms of
noname [10]

Answer:

Each inhalation has 750 micrograms of metaproterenol sulfate.

Step-by-step explanation:

First step: How many miligrams are there in each inhalation.This can be solved by a rule of three problem.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.

In this step, our measures are:

- The number of inhalations.

- The quantity inhaled.

As the number of inhalations increases, so does the quantity inhaled. This means that this is a direct rule of problem.

300 inhalations contains 225mg of metaproterenol sulfate. How many miligrams are in a inhalation?

300 inhalations - 225mg

1 inhalation - xmg

300x = 225

x = \frac{225}{300}

x = 0.75mg

Each inhalation has 0.75mg of metaproterenol sulfate.

Final step: Conversion of 0.75mg to micrograms.

Each mg has 1000 micrograms. So:

1mg - 1000 micrograms

0.75mg - x micrograms

x = 1000*0.75

x = 750 micrograms

Each inhalation has 750 micrograms of metaproterenol sulfate.

7 0
3 years ago
How do you solve (7^-1)^-1 and 5^2 * 5^4 * 5^-3
Katyanochek1 [597]

Answer:

Step-by-step explanation:

exponents raised to a - power  is an inverse function probably not the right word

       a^-b    =  1/(a^b)     example       4^-2   = 1/(4^2)     =  1/16

so   (7^-1)^-1  is a double inverse which is back to the original number  7

      inverted 7 twice

      (7^-1)^-1     = (1/7)^-1     =  1/(1/7)     =   7     trust me or use your calculator

since the coeffients are the same  just add the powers...  some exponent rule

     5^2 * 5^4 * 5^-3   = 5^(2+4-3)   = 5³

here is it written out

5^2 * 5^4 * 5^-3    = 5²  ×   5^4   ×  5^-3    =   (5×5) × (5×5×5×5)  × (1/5×1/5×1/5)

    5×5 × 5× (5×5×5  × 1/5×1/5×1/5)           (5×5×5  × 1/5×1/5×1/5)  = 1

    5×5×5    = 5³

   so

7 0
3 years ago
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