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geniusboy [140]
3 years ago
12

Help me solve this please!!!!

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
5 0
The answer is e u got this
lorasvet [3.4K]3 years ago
4 0
12. The answer is E
13. The answer is B
14. The answer is C
15. The answer is F




Hope this Helps :)
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If 15 is 25% of a value, what is that value? A. 60 B. 65 C. 40 D. 75
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It’s 60..................
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Solve for x. Triangles below are similar. <br><br> a) 13<br> b) 10<br> c) 4<br> d) 3
Reptile [31]

Answer:

the answer is 4 (option C)

Step-by-step explanation:

Since the triangles are similar, and in triangle UTV both sides are equal, we can consider QTR also has two equal sides.

therefore, the equation forms:

13x + 3 = 55

13x = 55 - 3

13x = 52

x = 52/13

x = 4

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3 years ago
What is the volume of the prism?<br><br> 14 m3<br> 24 m3<br> 30 m3<br> 44 m
geniusboy [140]

Answer:

the answer is 24 m3

                                             

6 0
3 years ago
Mr. Jones jogs the same route each day. The amount of time he jogs is inversely proportional to his jogging rate.
german

Answer is option C

Mr. Jones jogs the same route each day. The amount of time he jogs is inversely proportional to his jogging rate.

time= \frac{k}{rate}

k is the constant of proportionality

We check with each option and identify which option gives us same K value

(a) 4 mph for 2.5 hours and 6 mph for 3.75 hours

2.5= \frac{k}{4} so k = 10

3.75= \frac{k}{6} so k = 22.5

K values are not same

(b) 3 mph for 2 hours and 4.5 mph for 3 hours

2= \frac{k}{3} so k = 6

3= \frac{k}{4.5} so k = 13.5

K values are not same

(c) 4 mph for 2.5 hours and 5 mph for 2 hours

2.5= \frac{k}{4} so k = 10

2= \frac{k}{5} so k =10

K values are  same .

Answer is option C


3 0
3 years ago
Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form
Alex787 [66]

Answer:

y=-\frac{2}{5}x-\frac{1}{5}

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

  • m is the slope
  • b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

m = -\frac{2}{5}

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-\frac{2}{5}x + b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

  • (-3,1). When x of the line is -3, y of the line must be 1.
  • (2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: y=-\frac{2}{5}x + b. b is what we want, the --\frac{2}{5} is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

  • (-3,1). y = mx + b or 1=-\frac{2}{5} * -3 + b, or solving for b: b = 1-(-\frac{2}{5})(-3).b = -\frac{1}{5}.
  • (2,-1). y = mx + b or -1=-\frac{2}{5} * 2 + b, or solving for b: b = 1-(-\frac{2}{5})(2). b = -\frac{1}{5}.

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points  (-3,1) and (2,-1) is y=-\frac{2}{5}x-\frac{1}{5}

8 0
3 years ago
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