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Volgvan
3 years ago
5

For the triangle shown below, find the circumcenter and orthocenter

Mathematics
1 answer:
natta225 [31]3 years ago
5 0

Answer: Circumcenter = \bold{\bigg(1,-\dfrac{3}{2}\bigg)}    Orthocenter = (-4, -6)

<u>Step-by-step explanation for Circumcenter:</u>

Step 1: Find the midpoint of a line:<em> I chose (-4, 3) and (-4, -6)</em>

\bigg(\dfrac{-4-4}{2},\dfrac{3-6}{2}\bigg)=\bigg(\dfrac{-8}{2},\dfrac{-3}{2}\bigg) = \bigg(-4,-\dfrac{3}{2}\bigg)

Step 2: Find the perpendicular line that passes through that point:

Since it is a vertical line, the perpendicular line is y=-\dfrac{3}{2}

Step 3: repeat Steps 1 and 2 for another line: <em> chose (-4, -6) and (6, -6)</em>

\bigg(\dfrac{-4+6}{2},\dfrac{-6-6}{2}\bigg)=\bigg(\dfrac{2}{2},\dfrac{-12}{2}\bigg) = (1,-6)

Since it is a horizontal line, the perpendicular line is: x = 1

Step 4: Find the intersection of the two lines \bigg(y=-\dfrac{3}{2}\ \text{and}\ x = 1\bigg)

Their point of intersection is: \bigg(1, -\dfrac{3}{2}\bigg)

*************************************************************************************

<u>Step-by-step explanation for Orthocenter:</u>

Step 1: Find the perpendicular slope of a line: <em>I chose (-4, 3) and (-4, -6)</em>

Slope is undefined. Perpendicular slope is 0.

Step 2: Use the Point-Slope formula to find the equation of the line that passes through the vertex that is opposite of the line from Step 1 and has the perpendicular slope (found in Step 1).  

Vertex (6, -6) and m⊥ = 0  ⇒  y + 6 = 0(x - 6)  ⇒  y = -6

Step 3: repeat Steps 1 and 2 for another line: <em> chose (-4, -6) and (6, -6)</em>

Slope is 0. Perpendicular slope is undefined (x = __ )

Vertex (-4, 3) and m⊥ = undefined  ⇒  x = -4

Step 4: Find the intersection of the two lines (y=-6\ \text{and}\ x = -4)

Their point of intersection is: (-4, -6)

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