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mixas84 [53]
3 years ago
14

Complete the statement. Enter your answer in the box. Use fraction strips or number lines to help.

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
4 0

Answer:

you did not post a question?

Step-by-step explanation:

You might be interested in
2. Which equation in standard form has a graph that passes through the point (-5,8) and has a
atroni [7]

Answer:

a

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - \frac{1}{5}, thus

y = - \frac{1}{5} x + c ← is the partial equation

To find c substitute (- 5, 8) into the partial equation

8 = 1 + c ⇒ c = 8 - 1 = 7

y = - \frac{1}{5} x + 7 ← in slope- intercept form

Multiply through by 5

5y = - x + 35 ( add x to both sides )

x + 5y = 35 ← in standard form → a

3 0
3 years ago
Please Help please please
nlexa [21]

Answer:

5.25

Step-by-step explanation:

Take the distance between the two points and divide by 2.

The distance between the two is 10.5 (9.1-(-1.4))

Divide by two to find the midpoint.

6 0
3 years ago
Read 2 more answers
Are these answers correct? If not, what would the answers be?
Ludmilka [50]
Yes you have the correct answers for each of the four problems. Nice work.

For anyone curious,
rd = removable discontinuity
id = infinite discontinuity
c = continuous
7 0
3 years ago
In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that
attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0
3 years ago
I NEED HELP PLEASEEEEEE
dybincka [34]

Answer:

A. The function is always decreasing

Step-by-step explanation:

we read a graph from left to right, so we can always compare the increase/decrease of a function by seeing how an x value compares with an x value to the left

(I am aware that this paragraph is really confusing)

we can see that as x increases, from -∞ to 0,

y decreases in correspondence

and that as x increases, from 0 to ∞,

y decreases in correspondence also

So, even though the graph doesn't quite look like it, when x < 0; the function decreases, when x > 0; function decreases--so the function is always decreasing

hope this helps!! have a lovely day :)

5 0
2 years ago
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