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Delicious77 [7]
3 years ago
15

I really need help please help me

Mathematics
1 answer:
Savatey [412]3 years ago
8 0
Okay here all the answers:

Image one:
11) D.
12) D.
13) B
Second image:
1) D (if not B)
2) A
3) D
4) B
5) C
6) D
7) C
8) B
9) C (if not D)
10) D

I hope this helped you!! :)

Tell me if you want step by step on any of them.

Keep rocking!!

(When I say “if not __” that means I was a bit unsure, but mostly confident. So don’t worry, just go with the first option. :)
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What are the x-intercepts of the function f(x)=0.5x^2+2x-6
Darya [45]

Answer:

(2,0) (-6,0)

Step-by-step explanation:

Solve: 0.5x^2+2x-6=0

The answer you get is:

x=2, x=-6

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3 years ago
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RSB [31]

Answer:

Step-by-step explanation:

8 0
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Help and explain pls and thankyouuu
Drupady [299]

Answer:

f(-3.2) = -7.2

Step-by-step explanation:

Here, we want to calculate f(-3.2)

What we have to do here is to substitute-3.2 for x in the equation for f(x)

Mathematically, we have this as;

f(-3.2) = -3.2-4 = -7.2

4 0
3 years ago
The average daily rainfall in Seattle for the month of June has a mean absolute deviation of 1.3 inches. What conclusion can you
Oduvanchick [21]

Using the mean absolute deviation, it can be concluded that the daily rainfall volume differs from the mean by an average of 1.3 inches.

<h3>What is the mean absolute deviation of a data-set?</h3>
  • The mean of a data-set is given by the sum of all observations divided by the number of observations.
  • The mean absolute deviation of a data-set is the sum of the absolute value of the difference between each observation and the mean, divided by the number of observations.
  • The mean absolute deviation represents the average by which the values differ from the mean.

In this problem, the mean absolute deviation is of 1.3 inches, hence, it can be concluded that the daily rainfall volume differs from the mean by an average of 1.3 inches.

More can be learned about the mean absolute deviation at brainly.com/question/3250070

6 0
2 years ago
Nick can read 3 pages
xenn [34]
Ok...so what are you trying to say here. So that I can help.
4 0
3 years ago
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