Answer:
1
Step-by-step explanation:
Thanks!!!!!!!!!!!!!!!
Answer:
See below.
Step-by-step explanation:
I will assume that 3n is the last term.
First let n = k, then:
Sum ( k terms) = 7k^2 + 3k
Now, the sum of k+1 terms = 7k^2 + 3k + (k+1) th term
= 7k^2 + 3k + 14(k + 1) - 4
= 7k^2 + 17k + 10
Now 7(k + 1)^2 = 7k^2 +14 k + 7 so
7k^2 + 17k + 10
= 7(k + 1)^2 + 3k + 3
= 7(k + 1)^2 + 3(k + 1)
Which is the formula for the Sum of k terms with the k replaced by k + 1.
Therefore we can say if the sum formula is true for k terms then it is also true for (k + 1) terms.
But the formula is true for 1 term because 7(1)^2 + 3(1) = 10 .
So it must also be true for all subsequent( 2,3 etc) terms.
This completes the proof.
x < -23/2
Step-by-step explanation:
you open the bracket first
LHS
3-(2x - 5)
-6x+15
RHS
-4(x+2)
=-4x-8
therefore:
-6x+15 < -4x-8
By collecting the like terms
-6x+4x < -8-15
=-2x<-23
Divide both side by -2x
-2x/-2 < -23/-2
x < -23/2
2(x) - [12 + 2y) ➡ 0
2(x - y - 6)
2 ➡0 {It doesn't have any solution for the equation}
x - y - 6 ➡0
y ➡ 6 over -1 ; x ➡6 over 1
The slope = 1
Therefore your answer would have to be ➡
y= 6 over -1 ; x = 6 over 1 ; slope = 1
Answer:
Taryn charges $12.50 per lawn.