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Alja [10]
2 years ago
8

I NEED HELP PLEASEEEEEE

Mathematics
1 answer:
dybincka [34]2 years ago
5 0

Answer:

A. The function is always decreasing

Step-by-step explanation:

we read a graph from left to right, so we can always compare the increase/decrease of a function by seeing how an x value compares with an x value to the left

(I am aware that this paragraph is really confusing)

we can see that as x increases, from -∞ to 0,

y decreases in correspondence

and that as x increases, from 0 to ∞,

y decreases in correspondence also

So, even though the graph doesn't quite look like it, when x < 0; the function decreases, when x > 0; function decreases--so the function is always decreasing

hope this helps!! have a lovely day :)

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The diameter of a circle measures 7 5/6 inches. What is the radius of the circle? Enter your answer as a mixed number in the box
andrew-mc [135]

The radius of the circle expressed as a mixed number is:  3\frac{11}{12} inches.

<h3>What is the Radius of a Circle?</h3>

Radius of a circle = half the measure of the diameter of a circle.

Given:

diameter of a circle = 7\frac{5}{6} inches

Therefore:

Radius of the circle = 1/2(7\frac{5}{6})

= 1/2(47/6)

= (1 × 47)/(2 × 6)

= 47/12

= 3\frac{11}{12} inches.

Therefore, the radius of the circle expressed as a mixed number is:  3\frac{11}{12} inches.

Learn more about radius of a circle on:

brainly.com/question/24375372

4 0
2 years ago
The weights of certain machine components are normally distributed with a mean of 8.04 g and a standard deviation of 0.08 g. Fin
NISA [10]

Answer:

The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

Step-by-step explanation:

We are given that

Mean, \mu=8.04 g

Standard deviation, \sigma=0.08g

We have to find the two weights that separate the top 3% and the bottom 3%.

Let x be the weight of  machine components

P(Xx_2)=0.03

P(X

=0.03

From z- table we get

P(Z1.88)=0.03

Therefore, we get

\frac{x_1-8.04}{0.08}=-1.88

x_1-8.04=-1.88\times 0.08

x_1=-1.88\times 0.08+8.04

x_1=7.8896

\frac{x_2-8.04}{0.08}=1.88

x_2=1.88\times 0.08+8.04

x_2=8.1904

Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

5 0
2 years ago
6
IgorC [24]

Answer:

12 less than or equal to 2

Step-by-step explanation:

7 0
3 years ago
Choose all distances that are equivalent to 1/2 mile.
damaskus [11]

Answer:

A, C, and E.

Step-by-step explanation:

I looked up what half a mile was in meters, yards, and feet, and it told me these were the right answers.

6 0
2 years ago
2. When a large truckload of mangoes arrives at a packing plant, a random sample of 150 is selected and examined for
kirza4 [7]

a) The 90% confidence interval of the percentage of all mangoes on the truck that fail to meet the standards is: (7.55%, 12.45%).

b) The margin of error is: 2.45%.

c) The 90% confidence is the level of confidence that the true population percentage is in the interval.

d) The needed sample size is: 271.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions has the bounds given by the rule presented as follows:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The variables are listed as follows:

  • \pi is the sample proportion, which is also the estimate of the parameter.
  • z is the critical value.
  • n is the sample size.

The confidence level is of 90%, hence the critical value z is the value of Z that has a p-value of \frac{1+0.90}{2} = 0.95, so the critical value is z = 1.645.

The sample size and the estimate are given as follows:

n = 150, \pi = \frac{15}{150} = 0.1

The margin of error is of:

M = z\sqrt{\frac{0.1(0.9)}{150}} = 0.0245 = 2.45\%

The interval is given by the estimate plus/minus the margin of error, hence:

  • The lower bound is: 10 - 2.45 = 7.55%.
  • The upper bound is: 10 + 2.45 = 12.45%.

For a margin of error of 3% = 0.03, the needed sample size is obtained as follows:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.1(0.9)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.1(0.9)}

\sqrt{n} = \frac{1.645\sqrt{0.1(0.9)}}{0.03}

(\sqrt{n}})^2 = \left(\frac{1.645\sqrt{0.1(0.9)}}{0.03}\right)^2

n = 271 (rounded up).

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

3 0
1 year ago
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