PLEASE HELP MEE!!b znzjz

PLEASE ANSWER I REALLY NEED IT I WILL GIVE 25 POINTS

jonny [76]

Answer:

I don´t know fully but you add by ones on top and add by threes on the bottom

Step-by-step explanation:

3 0

2 years ago

In the figure, PQ is parallel to RS. The length of RP is 2 cm; the length of PT is 18 cm; the length of QT is 27 cm. What is the

Sidana [21]

Step 1

Find the value of TS

we know that

if PQ is parallel to RS. then triangles TRS and TPQ are similar

so

$\frac{TR}{TP} =\frac{TS}{QT}$

solve for TS

$TS =\frac{TR*QT}{TP}$

we have

$RP=2\ cm\\TP=18\ cm\\QT=27\ cm$

$TR=TP+RP\\TR=18+2=20\ cm$

substitute

$TS =\frac{20*27}{18}$

$TS =30\ cm$

Step 2

Find the value of SQ

we know that

$SQ=TS-QT$

we have

$TS =30\ cm$

$QT=27\ cm$

substitute

$SQ=30\ cm-27\ cm=3\ cm$

therefore

the answer is

the value of SQ is $3\ cm$

6 0

2 years ago

Read 2 more answers

a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l

GrogVix [38]

Answer:

$\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}$

Step-by-step explanation:

The equation of a line:

$y=mx+b$

We have

$m=\dfrac{2}{3}$

substitute:

$y=\dfrac{2}{3}x+b$

The formula of a distance between a point and a line:

General form of a line:

$Ax+By+C=0$

Point:

$(x_0,\ y_0)$

Distance:

$d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}$

Convert the equation:

$y=\dfrac{2}{3}x+b$ |subtract $y$ from both sides

$\dfrac{2}{3}x-y+b=0$ |multiply both sides by 3

$2x-3y+3b=0\to A=2,\ B=-3,\ C=3b$

Coordinates of the point:

$(0,\ 0)\to x_0=0,\ y_0=0$

substitute:

$d=4$

$4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}$

$4=\dfrac{|3b|}{\sqrt{13}}\qquad|$ |multiply both sides by $\sqrt{13}$

$4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}$ |divide both sides by 3

$b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}$

Finally:

$y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}$

4 0

2 years ago

Write an equation of the form y=a sin bx or y= a cos bx to describe the graph below.

kakasveta [241]

we conclude that the graphed equation is:

y = 4*cos(pi*x)

<h3></h3><h3>Which trigonometric equation is the one in the graph?</h3>

First, we can see that the graphed function is even, so we know that it wiill be a cosine.

We also can see that the maximum is 4 and the minimum is -4, so the amplitude is 4.

Then we have something like:

y = 4*cos(b*x)

To find the value of b, we can use the fact that the zeros of the function are at x = ±1/2

Then:

b*1/2 = pi/2

b = pi

Finally, we conclude that the graphed equation is:

y = 4*cos(pi*x)

If you want to learn more about trigonometric equations:

brainly.com/question/8120556

#SPJ1

4 0

1 year ago

Read 2 more answers

PLEASE HELP!!!!!Find the equation of each line and then put each equation into the form Ax+By=C where A,B, and C are integers

shutvik [7]

Answer:

y-5x-7=0

Step-by-step explanation:

m = -2-3/1-2

m=5

y-y1 = m(x-x1)

y-2=5(x+3)

y-2=5x +5

y-5x-7=0

4 0

3 years ago

PLEASE HELP MEE!!bznzjz​

PLEASE HELP MEE!!bznzjz