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3 years ago

Which shows two triangles that are congruent by AAS? A, B, C, or D

Mathematics

2 answers:

alexira [117]3 years ago

8 0

Answer: (A) shows two triangles that are congruent by AAS.

Explanation:-

AAS (Angle-Angle-Side) postulate states that if two angles and the non-included side one triangle are equal to the two angles and the non-included side of the another triangle, then the two triangles are said to be congruent.

In figure A we have two angles and the non-included side one triangle are equal to the two angles and the non-included side of the next triangle attached to it ,thus by AAS postulate they are congruent.

Rest of the other figures do not have two angles equal in both the triangles.

Thus only A shows two triangles that are congruent by AAS.

Iteru [2.4K]3 years ago

3 0

The Answer is A. Hope I helped!

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What is the measure of angle A?

I am Lyosha [343]

First you have to find the angle B (check attachment)

$B = 180^{\circ} - 137^{\circ} = 43^{\circ}\\$

Then you can find the last angle inside the triangle, which I'll call C

$C = 180^{\circ} - 102^{\circ} - 43^{\circ} = 35^{\circ}$

Now you can find angle A

$A = 180^{\circ} - C = 180^{\circ} - 35^{\circ} = 145^{\circ}$

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3 years ago

((PLEASE HELP ASAP!! D:)) Natasha bought a tennis racket that was marked down in price, p, by 20%. Write an expression with TWO

kumpel [21]

Answer: p - 0.2p

Step-by-step explanation:

Given the following :

Original Price of tennis racket = p

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3 years ago

If f(x) =3x-5 them find values of f(3) and f(-7). please explain step by step

LenKa [72]

Answer:

f(3) = 4

f(-7) = -26

Step-by-step explanation:

Hi there!

$f(x) =3x-5$

To find f(3), replace every x with 3:

$f(3) =3(3)-5\\f(3) =9-5\\f(3) =4$

Therefore, f(3)=4.

$f(x) =3x-5$

To find f(-7), replace every x with -7:

$f(-7) =3(-7)-5\\f(-7) =-21-5\\f(-7) =-26$

Therefore, f(-7)=-26.

I hope this helps!

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2 years ago

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Vlad [161]

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b. $v(t)$ gives the Johanna's velocity at time $t$ . The magnitude of her velocity, or speed, is $|v(t)|$ . Integrating this would tell us the total distance she has traveled whilst jogging.

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$\displaystyle\int_0^{40}|v(t)|\,\mathrm dt=12\cdot200+8\cdot240+4\cdot220+16\cdot150=7600$

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