

- <u>The </u><u>sum</u><u> </u><u>of </u><u>the </u><u>number </u><u>in </u><u>each </u><u>of </u><u>the </u><u>four </u><u>rows </u><u>is </u><u>the </u><u>same </u>
- <u>The </u><u>sum </u><u>of </u><u>the </u><u>numbers </u><u>in </u><u>each </u><u>of </u><u>the </u><u>three </u><u>columns </u><u>is </u><u>the </u><u>same</u>
- <u>The </u><u>sum </u><u>of </u><u>any </u><u>row </u><u>does </u><u>not </u><u>equal </u><u>the </u><u>sum </u><u>of </u><u>any </u><u>column </u>

<u>According </u><u>to </u><u>the </u><u>Second</u><u> </u><u>rule </u><u>:</u><u>-</u>


<u>According </u><u>to </u><u>the </u><u>first </u><u>rule </u><u>:</u><u>-</u><u> </u>


<u>From </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>got </u><u>:</u><u>-</u>



<u>Subsitute </u><u>(</u><u>3</u><u>)</u><u> </u><u>in </u><u>(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>:</u><u>-</u>


<u>We</u><u> </u><u>can </u><u>write </u><u>it </u><u>as </u><u>:</u><u>-</u>



<u>Subsitute </u><u>the </u><u>value </u><u>of </u><u>c </u><u>and </u><u>e </u><u>in </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>


<u>Now</u><u>, </u>









Hence, The value of a, b, c, d and e is 23, 31 ,60 ,33 and 51 .
So 1/12 of all dogs are in hound
of the hound gropu, 3/10 is english foxhounds
find what fraciton of all adogs are english foxhounds
so 3/10 of 1/12
in math 'of' means multiply with fractions so
3/10 times 1/12=(3 times 1)/(10 times 12)=3/120=1/40
1/40 of the dogs were english foxhounds
Answer:
It's dividing by 3 everytime, so 1/3
Step-by-step explanation:
Answer:
Option D.The ratio of the radius of a circle to its circumference
Step-by-step explanation:
<em>Verify each statement</em>
A) The ratio of the circumference of a circle to its diameter
The statement is True
Because

so

B) Approximated to be 3.14
The statement is True
Because 
C) Approximated to be 22/7
The statement is True
Because

D) The ratio of the radius of a circle to its circumference
The statement is not True
Because

Answer:
x=-10
Step-by-step explanation:

Add 11 on both sides.
