That would be 16 because all the others are multiples of 3.
<em>The </em><em>right</em><em> answer</em><em> is</em><em> </em><em>of </em><em>option</em><em> </em><em>D.</em>
<em>
</em>
<em>In </em><em>the </em><em>given </em><em>graph,</em><em> </em><em>X </em><em>is </em><em>greater </em><em>than </em><em>4</em><em> </em><em>and </em><em>X </em><em>equals </em><em>to </em><em>4</em><em>.</em>
<em>Hope </em><em>it</em><em> helps</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
Answer
z11.7 is between 1 and 2 standard deviations of the mean.
Step-by-step explanation:
The slope of the perpendicular line is -1/m.
it passes through the point (a,c) therefore:-
y - c = -1/m(x - a)
y = -1/m x + a/m + c answer
Parallel line:-
c = m(a) + b
b = c - ma
y = mx + c - ma Answer
Micah was asked to add the following expressions:

First, he combined like terms in the numerator and kept the common denominator
First step is correct. He added the like terms in the numerator, because the denominators are same.

So he got , 
In the next step, he cannot cancel out x^2 from the top and bottom . Because x-4 and 3x+2 are added with x^2
If we have x^2 is multiplied with other terms at the top and bottom , then we can cancel out x^2.
So Micah added the expression incorrectly. Final answer is not correct.