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Alchen [17]
2 years ago
11

If january 1st was on a tuesday, on what day of the week would february 1 fall?

Mathematics
2 answers:
Margaret [11]2 years ago
5 0

Answer:

In America it would be a Monday.

Step-by-step explanation:

It matters where you live.

vovikov84 [41]2 years ago
3 0
It would be on friday
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The median number of coloring contests won by 4 kids in a certain year is 5. The range of number of contests won by those kids t
Orlov [11]
True
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7 0
2 years ago
HELP!!
BabaBlast [244]

Answer:

8 units

Step-by-step explanation:

it should be 8, EH is practically AD, if you match ABCD's letters and numbers with EFGH's. I hope this helps!

3 0
2 years ago
20 + 8(q - 11) = -12
Simora [160]

Step-by-step explanation:

try to impose the process of elimination and see if that helps

3 0
3 years ago
Write the equation of the circle with center (−1, −3) and (−7, −5) a point on the circle.
Pepsi [2]
So, we know the center is at -1, -3, hmmm what's the radius anyway?

well, the radius will be the distance from the center to any point on the circle, it just so happen that we know -7, -5 is on it, thus

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -1 &,& -3~) 
%  (c,d)
&&(~ -7 &,& -5~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
r=\sqrt{[-7-(-1)]^2+[-5-(-3)]^2}\implies r=\sqrt{(-7+1)^2+(-5+3)^2}
\\\\\\
r=\sqrt{36+4}\implies r=\sqrt{40}\\\\
-------------------------------

\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{-1}{ h},\stackrel{-3}{ k})\qquad \qquad 
radius=\stackrel{\sqrt{40}}{ r}
\\\\\\\
[x-(-1)]^2+[y-(-3)]^2=(\sqrt{40})^2\implies (x+1)^2+(y+3)^2=40
5 0
3 years ago
What is the sum of the first five terms of the geometric sequence in which a1=10 and r=1/2?
Tomtit [17]
(10(1-(1/2)^5)/1-(1/2) = 

20(1-1/32)
=155/8
5 0
3 years ago
Read 2 more answers
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