Answer : The number of unpaired electrons in the = 2
The bond order of is, 2
Explanation :
According to the molecular orbital theory, the general molecular orbital configuration will be,
As there are 9 electrons present in fluorine.
The number of electrons present in molecule = 2(9) = 18 - 2 = 16
The molecular orbital configuration of molecule will be,
The number of unpaired electrons in the = 2
The formula of bond order =
The bonding order of =
The bond order of is, 2
Answer:
<u>1</u>Al₄C₃ + <u>12</u>H₂O → <u>3</u>CH₄ + <u>4</u>Al(OH)₃
Explanation:
<u>SOLUTION :-</u>
Balance it by using 'hit & trial' method , and you'll get the answer :-
<u>1</u>Al₄C₃ + <u>12</u>H₂O → <u>3</u>CH₄ + <u>4</u>Al(OH)₃
<u>VERIFICATION :-</u>
<em>In reactant side of equation :-</em>
- Number of atoms in Al = 1×4 = 4
- Number of atoms in C = 1×3 = 3
- Number of atoms in H = 12×2 = 24
- Number of atoms in O = 12×1 = 12
<em>In product side of equation :-</em>
- Number of atoms in C = 3×1 = 3
- Number of atoms in H = (3×4) + 4(1×3) = 24
- Number of atoms in Al = 4×1 = 4
- Number of atoms in O = 4(1×3) = 12
Number of atoms of each element is equal in both reactant & product side of equation. Hence , the equation is balanced.
Answer:
the catalyst is the two gray dots
What are the answers you can pick
NO2- +7H+ + 6e->> NH3 + 2H2O ( N goes from +3 to -3)
<span>Al + 2 H2O >> AlO2- + 4H+ + 3e- </span>
<span>NO2- + 2Al + 2H2O >> NH3 + 2AlO2- + H+ </span>
<span>add OH- on the left and on the right </span>
<span>NO2- + 2 Al + H2O + OH- >> NH3 + 2 AlO2-</span>