Name the following alkyne: CH3CH₂C = CCH₂CH₂CH3
1 answer:
The given alkyne is Option A 3-heptyne
<h3>What is an Alkyne ?</h3>The hydrocarbon having at least one C-C triple bond is called an Alkyne.
It has the general formula of .
In the question it is being mentioned that it is an alkyne so there will be a triple bond and not a double bond.
It has been asked in the question that
CH3CH₂C ≡ CCH₂CH₂CH3 is which alkyne from the given option.
The counting of the Carbon chain is done from the left side and the Triple bond is at the 3rd Carbon , so 3-heptyne .
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Answer: 7.07 grams
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of require 1 mole of
Thus 0.052 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and
is the excess reagent.
As 1 mole of give = 1 mole of
Thus 0.052 moles of give =
of
Mass of
Thus 7.07 g of will be produced from the given masses of both reactants.