I need a a picture or the question
Answer:

Explanation:
Oxygen has eight eletrons and six valence electrons, giving it the electron configuration of
.
Answer:
the change in energy of the gas mixture during the reaction is 227Kj
Explanation:
THIS IS THE COMPLETE QUESTION BELOW
Measurements show that the enthalpy of a mixture of gaseous reactants increases by 319kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that -92kJ of work is done on the mixture during the reaction. Calculate the change of energy of the gas mixture during the reaction in kJ.
From thermodynamics
ΔE= q + w
Where w= workdone on the system or by the system
q= heat added or remove
ΔE= change in the internal energy
q=+ 319kJ ( absorbed heat is + ve
w= -92kJ
If we substitute the given values,
ΔE= 319 + (-92)= 227 Kj
With the increase in enthalpy and there is absorbed heat, hence the reaction is an endothermic reaction.
The volume at 100 mmHg : 0.656 L
<h3>
Further explanation</h3>
Boyle's Law
<em>At a constant temperature, the gas volume is inversely proportional to the pressure applied </em>

V₁=3.5 L
P₁=2.5 kPa=18,7515 mmHg
P₂=100 mmHg
