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2 years ago

Which of the following fractions is equivalent to (−13)÷(−6)? Select two that apply.

Mathematics

1 answer:

tangare [24]2 years ago

5 0

Answer:

D and F

Step-by-step explanation:

Please mark brainliest.

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Which is the correct way to write 602, 200,000,000,000,000,000,000 in scientific notation?

scoundrel [369]

Scientific notation is
n times 10^x
where 1≤n<10 and x is the number of places the decimal place moved (if it moved to the right, x is negative, if it moved to the left, x is positive)

602, 200,000,000,000,000,000,000.0
we see we need to move decimal to the left 23 spaces to here
6.022 times 10^23

answer is $6.022*10^{23}$

6 0

3 years ago

3x + 2y = 7

Lady bird [3.3K]

It would be the last option, (5, -4)

4 0

2 years ago

Two sides of a triangle have lengths 18cm and 40cm describe the possible lengths of the third side

Paraphin [41]

Answer:

Step-by-step explanation:

a taingle adds up to 180 degrees if that helps

5 0

3 years ago

In a particular game, a fair die is tossed. If the number of spots showing is either four or five, you win $1. If the number of

TiliK225 [7]

Answer:

The probability that you win at least $1 both times is 0.25 = 25%.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either you win at least $1, or you do not. Games are independent. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of winning at least $1 on a single game:

The die has 6 sides.

If it lands on 4, 5 or 6(either of the three sides), you win at least $1. So

$p = \frac{1}{2} = 0.5$

You are going to play the game twice.

This means that $n = 2$

The probability that you win at least $1 both times is

This is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.5)^{2}.(0.5)^{2} = 0.25$

The probability that you win at least $1 both times is 0.25 = 25%.

4 0

2 years ago

In a line of students ,Jenna is number 8.The teacher says the rule for a number pattern is add4.The first term 7.What number sho

balandron [24]

1. You have that the rule for a number pattern is add 4 and the <span>first term is 7.

2. Let's call "n" to the number in the line where each student is. Then, you can express this as below:

4n+7

3. So, you have:

Student N°1=4(1)+7=11
</span> Student N°2=4(2)+7=15
Student N°3=4(3)+7=19
Student N°4=4(4)+7=23
Student N°5=4(5)+7=27
Student N°6=4(6)+7=31
Student N°7=4(7)+7=35
Student N°8=4(8)+7=39
<span>
What number should Jenna say?

The answer is: 39</span>

4 0

3 years ago