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xenn [34]
3 years ago
8

What element is this?

Chemistry
2 answers:
Lady_Fox [76]3 years ago
5 0

Answer:

hydrogen and helium is the answer

katrin2010 [14]3 years ago
4 0

Answer: hydrogen and helium?

Explanation: it looks like the photo Is outer space and then hydrogen and helium is outer space so I think hydrogen and helium sorry if I’m wrong

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A gas occupies 3.8 L at -18° C and 975. torr. What volume would this gas occupy at STP?
Aleks04 [339]

To solve the question we will assume that the gas behaves like an ideal gas, that is to say, that there is no interaction between the molecules. Assuming ideal gas we can apply the following equation:

PV=nRT

Where,

P is the pressure of the gas

V is the volume of the gas

n is the number of moles

R is a constant

T is the temperature

Now, we have two states, an initial state, and a final state. The conditions for each state will be.

Initial state (1)

P1=975Torr=1.28atm

V1=3.8L

T1=-18°C=255.15K

Final state(2), STP conditions

P2=1atm

T2=273.15K

V2=?

We will assume that the number of moles remains constant, so the nR term of the first equation will be constant. For each state, we will have:

\begin{gathered} \frac{P_1V_1}{T_1}=nR \\ \frac{P_2V_2}{T_2}=nR \end{gathered}

Since nR is the same for both states, we can equate the equations and solve for V2:

\begin{gathered} \frac{P_{2}V_{2}}{T_{2}}=\frac{P_1V_1}{T_1} \\ V_2=\frac{P_{1}V_{1}}{T_{1}}\times\frac{T_2}{P_2} \end{gathered}

We replace the known values:

V_2=\frac{1.28atm\times3.8L}{255.15K}\times\frac{273.15K}{1atm}=5.2L

At STP conditions the gas would occupy 5.2L. First option

8 0
1 year ago
Which phrase describes properties of a solid?
Licemer1 [7]

Answer: fixed shape and volume

Explanation:

i took the quiz so its right

6 0
3 years ago
A(n) ________is your legal document issued by a government that gives an inventor exclusive rights to make use or sell intervent
Crazy boy [7]
Patent - Not sure if this is much of a Chem question dou.
7 0
4 years ago
Read 2 more answers
You make two dilutions. You take 83.52 mL of the stock solution and dilute to 500.0 mL to make Solution #1. You then add 52.27 m
kati45 [8]

Answer:

The answer to the question is;

The concentration of the Solution #1 in terms of molarity is

0.16704X moles/litre.

Explanation:

Let the concentration of the stock solution be X moles/liter

Therefore, 83.52 ml of the stock solution contains

83.52×(X/1000) moles

Dilution of 83.52 ml of X to 500 ml gives solution 1 with a concentration of

500 ml of solution 1 contains 83.52×(X/1000) moles

Therefore 1000 ml or 1 litre contains 2×83.52×(X/1000) moles = 0.16704X moles/litre

The molarity of solution 1 is 0.16704X moles/litre.

8 0
4 years ago
Do all dipole-dipole forces have the same strength?
n200080 [17]
Inter molecula force 
1- hydrogen bond 
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but not all dipole dipole has the same strength 
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3 years ago
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