Answer:
188.03K
Explanation:
The following data were obtained from the question:
T1 (initial temperature) =273K
V1 (initial volume) = 400mL
P1 (initial pressure) = 760mmHg
P2 (final pressure) = 380mmHg
V2 (final volume) = 551mL
T2 (final temperature) =?
Applying the general gas equation P1V1/T1 = P2V2/T2, the final temperature of the gas can be obtained as follow:
P1V1/T1 = P2V2/T2
760 x 400/273 = 380 x 551/T2
Cross multiply to express in linear form as shown below:
760 x 400 x T2 = 273 x 380 x 551
Divide both side by 760 x 400
T2 = (273 x 380 x 551)/(760 x 400)
T2 = 188.03K.
Therefore, at a temperature of 188.03K, the gas sample will have a volume of 551mL
