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3 years ago

What would be a simple way to block erosion

1 answer:

7 0

By applying some (compared to other things) simple steps, you can control and prevent soilwearing away! The four most common soil wearing away prevention methods are green plants, geotextiles, mulch, and (big walls to hold back water, soil, etc.). Green plants: The simplest andmost natural way to prevent wearing away is through planting green plants.

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Which of the following would cause the molecules in matter to change? Please help :)

cestrela7 [59]

Pressure what causes the molecules and matter to change .

5 0

3 years ago

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) B5H9(l) is a colorless liquid that will explode when exposed to oxygen. How much heat is released when 0.211 mol of B5H9 react

Tom [10]

Answer: The amount of heat released when 0.211 moles of $B_5H_9(l)$ reacts is 554.8 kJ

Explanation:

The chemical equation for the reaction of $B_5H_9$ with oxygen gas follows:

$2B_5H_9(l)+12O_2(g)\rightarrow 5B_2O_3(s)+9H_2O(l)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(5\times \Delta H_f_{(B_2O_3(s))})+(9\times \Delta H_f_{(H_2O(l))})]-[(2\times \Delta H_f_{(B_5H_9(l))})+(12\times \Delta H_f_{(O_2(g))})]$

We are given:

$\Delta H_f_{(H_2O(l))}=-285.4kJ/mol\\\Delta H_f_{(B_2O_3(s))}=-1272kJ/mol\\\Delta H_f_{(B_5H_9(l))}=73.2kJ/mol\\\Delta H_f_{(O_2(g))}=0kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(2\times (-1272))+(9\times (-285.4))]-[(2\times (73.2))+(12\times (0))]\\\\\Delta H_{rxn}=-5259kJ$

To calculate the amount of heat released for the given amount of $B_5H_9(l)$ , we use unitary method, we get:

When 2 moles of $B_5H_9(l)$ reacts, the amount of heat released is 5259 kJ

So, when 0.211 moles of $B_5H_9(l)$ will react, the amount of heat released will be = $\frac{5259}{2}\times 0.211=554.8kJ$

Hence, the amount of heat released when 0.211 moles of $B_5H_9(l)$ reacts is 554.8 kJ

7 0

3 years ago

Convert 19,864 mm to m

navik [9.2K]

19.864 meters would be the correct answer

3 0

3 years ago

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A(n) _____ crystal has 4 even sides.

irina [24]

I’m pretty sure the answer is triclinic

4 0

3 years ago

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How much heat is absorbed during production of 147 g of NO by the combination of nitrogen and oxygen?

marin [14]

Answer:

$\large \boxed{\text{105 kcal}}$

Explanation:

MM: 30.01

N₂ + O₂ ⟶ 2NO; ΔH = +43 kcal/mol

m/g: 147

Treat the heat as if it were a reactant in the reaction. Then you can write

N₂ + O₂ + 43 kcal ⟶ 2NO

The conversion factor is then 43 kcal/2 mol NO.

1. Moles of NO

$\text{Moles of NO} = \text{147 g NO} \times \dfrac{\text{1 mol NO}}{\text{30.01 g NO}} = \text{4.898 mol NO}$

2. Amount of heat

$\text{Heat} = \text{4.898 mol NO } \times \dfrac{\text{43 kcal}}{\text{2 mol NO}} = \text{105 kcal}\\\\\text{The reaction absorbs $\large \boxed{\textbf{105 kcal}}$}$

7 0

3 years ago