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Triss [41]
3 years ago
11

What would be a simple way to block erosion

Chemistry
1 answer:
Travka [436]3 years ago
7 0
By applying some (compared to other things) simple steps<span>, </span>you can control and prevent soilwearing away<span>! </span>The four most common soil wearing away prevention methods are green plants<span>, </span>geotextiles<span>, </span>mulch<span>, </span>and (big walls to hold back water, soil, etc.)<span>. </span>Green plants<span>: </span>The simplest andmost natural way to prevent wearing away is through planting green plants<span>.</span>
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A sample of an ideal gas at 1.00 atm and a volume of 1.50 L was placed in a weighted balloon and dropped into the ocean. As the
Lady bird [3.3K]

Answer:

Explanation:

Using Boyle's law

P₁ V₁ = P₂V₂ and temperature is constant

where P₁(pressure)  = 1.00atm, P₂ = 25 atm, V₁( volume) = 1.50L V₂ =

V₂ = ( P₁ V₁ ) / P₂ = ( 1 atm × 1.50L ) / 25 atm = 0.06 L

6 0
3 years ago
Thats wrong because i was taking a test and that was wrong its b
djyliett [7]
What do you mean do you need hekp?

6 0
3 years ago
1) The spectrum of lithium has a red line of 670.8 nanometers. (Remember 1 m = 1 X 109 nm) a. Convert the nanometer to meter usi
puteri [66]
<span>E = ħc / λ
 ħ = plancks constant = 6.626x10^-34 Js
c = speed of light = 2.999x10^8 m/s
λ = wavelength of light = 670.8x10^-9 m
 
E = (6.626x10^-34 Js) x (2.999x10^8 m/s) x (1 / 670.8x10^-9 m)
E = 2.962x10^-19 J

</span><span>3x10^8 / (670.8 * 10^-9) =4.47x10^14 Hz
 
4.47x10^14 Hz multiplied by plank's constant = 2.9634x10^-19
</span><span>
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
</span>
5 0
3 years ago
1. Which curve or point of a phase diagram would indicate the melting point at various temperatures and pressures?
yanalaym [24]
Which curve or point of a phase diagram would indicate the melting point at various temperatures and pressures?

fusion curve

3 0
3 years ago
Read 2 more answers
How much heat is required to melt 20 g of gold at 1064.18 °C with a heat of fusion of 64 J/g *
andrew-mc [135]

Answer:

1280J are required.

Explanation:

Heat of fusion is defined as the amount of heat required to change its state from liquid to solid at its melting point at constant pressure.

As heat of fusion of gold is 64J/g, there are required 64J to melt 1g of gold at its melting point. The energy required to melt 20g is:

20g * (64J/g) =

1280J are required

6 0
3 years ago
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