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sergij07 [2.7K]

3 years ago

15

Melissa’s family is driving out of state to her grandmother’s house. They know that it takes 20 gallons of gas to get there, and

the cost of three gallons of gasoline is $10.50. How much should the family budget to make the one-way trip?

1 answer:

sleet_krkn [62]3 years ago

3 0

Answer:

The family should budget $73.50 for 21 gallons of gasoline.

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Divide a 5-inch line into two parts so that one part (a) 2 1/4 inches shorter than the other; (b) 3 times the other.

Ilia_Sergeevich [38]

Part a), solve this system of equations:
x + y = 5
x - y = 2.25
2x = 7.25
x = 3.625
y = 1.375

part b), solve this system of equations:
x + y = 5
x = 3y
y = 1.25
x = 3.75

3 0

3 years ago

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Write the slope-intercept form of the equation of the line that has the same y-intercept as the black line shown and passes thro

Mazyrski [523]

Answer:

y = 0.5x + 2

Step-by-step explanation:

the y-intercept is 2, as shown in the graph

the slope is 0.5. this is because while the x-value goes up by 2, the y-value goes up by one (from 0, 2 to 2, 3).

using the slope formula of rise / run, you get 1/2, which is equal to 0.5

5 0

3 years ago

The perimeter of a semicircle is 5.14 feet. What is the semicircle’s area?

hammer [34]

$\bf \textit{circumference of a semi-circle}\\\\
C=\pi r\qquad 
\begin{cases}
r=radius\\
-----\\
C=5.14
\end{cases}\implies 5.14=\pi r\implies \boxed{\cfrac{5.14}{\pi }=r}\\\\
-------------------------------\\\\
\textit{area of a semi-circle}\\\\
A=\cfrac{\pi r^2}{2} \implies A=\cfrac{\pi }{2}r^2\implies A=\cfrac{\pi }{2}\left( \boxed{\cfrac{5.14}{\pi }} \right)^2
\\\\\\
A=\cfrac{\pi }{2}\implies \cfrac{5.14^2}{\pi ^2}\implies A=\cfrac{26.4196}{2\pi }\implies A=\cfrac{13.2098}{\pi }$

5 0

3 years ago

Please help me it needs to be correct

dimaraw [331]

Answer:

4(3m^3-2m^2+4m+2)

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Una piscina rectangular de 15 metros de largo por 9 metros de ancho està rodeada por un

stira [4]

Answer: 2 meters.

Step-by-step explanation:

Let w = width of the cement path.

Dimensions of pool : Length = 15 meters , width = 9 meters

Area of pool = length x width = 15 x 9 = 135 square meters

Along width cement path, the length of region = $2w+15$

width = $2w+9$

Area of road with pool = $(2w+15) (2w+9)$

$= 4w^2+30w+18w+135\\\\=4w^2+48w+135$

Area of road = (Area of road with pool ) -(area of pool)

$\Rightarrow\ 112 =4w^2+48w+135- 135\\\\\Rightarrow\ 112= 4w^2+48w\\\\\Rightarrow\ 4 w^2+48w-112=0\\\\\Rightarrow\ w^2+12w-28=0\ \ \ [\text{Divide both sides by 4}]\\\\\Rightarrow\ w^2+14w-2w-28=0\\\\\Rightarrow\ w(w+14)-2(w+14)=0\\\\\Rightarrow\ (w+14)(w-2)=0\\\\\Rightarrow\ w=-14\ or \ w=2$

width cannot be negative, so w=2 meters

Hence, the width of the road = 2 meters.

8 0

4 years ago