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Elena L [17]
3 years ago
14

A small plane is flying northeast at a speed of 200 mph. A wind blows due west at 28 mph. Find the resultant speed and direction

of the plane.
Mathematics
1 answer:
Allushta [10]3 years ago
5 0

Answer:

The resultant speed = 181.3 mph

The final direction = 38.7° northeast.

Step-by-step explanation:

We need to find the component in the x-direction and in the y-direction of the speed:

For the plane:

v_{p_{x}} = 200cos(45) = 141.42

v_{p_{y}} = 200sin(45) = 141.42

For the wind we have:

v_{w_{x}} = -28

v_{w_{y}} = 0

Now, the total speed in the x-direction and  in the y-direction is:

V_{x} = v_{p_{x}} + v_{w_{x}} = 141.42 - 28 = 113.42

V_{y} = v_{p_{y}} + v_{w_{y}} = 141.42

Hence, the resultant speed is:

V = \sqrt{V_{x}^{2} + V_{y}^{2}} = \sqrt{(113.42)^{2} + (141.42)^{2}} = 181.3 mph

Finally, the direction of the plane is:

tan(\theta) = \frac{V_{y}}{V_{x}} = \frac{141.42}{113.42} = 1.25

\theta = 51.3 ^{\circ}

\theta = 90 - 51.3 = 38.7 ^{\circ}

The plane is moving at 38.7° northeast.

I hope it helps you!

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