We are given with the equation y"+ 9 y = t^2 * e^3 t + 6 and asked to determine the general solution to this equation. we convert the equation into r^2 + 9 = 0. The solution to this equation is r = +/- 3i. This solution converted to trigonometric function is equivalent to <span>y</span>= <span>C1 </span>cos3t + <span>C2 </span>sin<span>3t. </span>
The answer would be -4 1/10
Answer:
y^1 = log5/log9 & y^2 = 7 - 3x
Answer:
the answer is A
Step-by-step explanation:
cross multiply 16×4 =64
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