Answer:
<em>In the next year, Anthony worked 2,084 hours</em>
Step-by-step explanation:
Anthony worked 1,697 hours in 2010.
We also know Anthony worked 22.8% more hours than in 2010.
The problem requires to calculate how much did Anthony work in the next year.
It can be calculated as follows:
Take 22.8% of 1,697:
Now calculate by adding it to the original number of hours:
1,697 + 387 = 2,084 hours
In the next year, Anthony worked 2,084 hours
--8+4+6=2
Hope it helps :-)
Can you expand the question into math formula? Please make it clear
Well, 1x5=5 and 2x5=10 so 3x5=15
Answer:
4.4N, 263.4°
Step-by-step explanation:
The sum of all forces must add to zero:
The forces in the x-plane:
∑F = 3N + (cos 120°)*5N + x = 0
x = -(3N + (cos 120°)*5N)
x = -0.5N
The forces in the y-plane:
∑F = (sin 120°)*5N + y = 0
y = -(sin 120°)*5N = -√(3/4)*5N = -4.3N
The magnitude of the unknown force U is:
U = √(x² + y²) = √19 = 4.4N
The direction is given by:
tanФ = y/x
Ф = 263.4°
