Please help right away

2(2x - 4) = 3(x + 4) Please solvvvvvve :'(

Zanzabum

1) $2(2x -4) = 3(x +4)


$

2) $4x - 8$

3) $3x+12$

4) $1x - 8 = 12$

5) $1x = 20$

Answer: $x = 20$

7 0

3 years ago

A region is bounded by y=e−3x, the x-axis, the y-axis and the line x = 3. If the region is the base of a solid such that each cr

grigory [225]

Answer:

0.333 $\pi$ units³

Step-by-step explanation:

Think process:

The equation is given as y = $e^{-3x}$

Let, y = f (x)

Therefore, $f (x) = e^{-3x}$

We know that the limits are y-axis and x= 3

Y-axis: x= 0

then limits are given as x= 0 and x = 3

Integrating gives:

$\int\limits^3_0 {e^{-3x} } \, dx$ = $\frac{-1}{3}e^{-3x}$ + C

calculating from x= 0 to x = 3, we know volume is given by $\pi \int\limits^a_b {f(x)} \, dx$

= $\pi$ [ $\frac{-1}{3} e^{-9} - (\frac{-1}{3} e^{0})$ ]

= $\pi$ [0.000041136 + 1/3]

= 0.333 $\pi$ units³

8 0

3 years ago

How much is 3×4+9÷6+44×77×777×00+9?

jarptica [38.1K]

Answer: $3*9+9/6+44*77*777*00+9$ , so using order of applications, it simplifies to 27+1.5+9 after multiplying and dividing, and the final answer is 37.5

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

In ten-pin bowling, the highest possible score in a single game is 300.

Natali [406]

Answer:

a) Is it possible for Fred to accomplish this? Yes

b) If it is possible, what score does he need in his next game? 293

Step-by-step explanation:

Step 1

Let us represent the number of games Fred bowled to get an average of 177 = X

His total points scored in that game would be

177 × X

= 177X

To achieve an average of 178 for his next game,

The total number of points he scored was 199, hence that is represented as:

178 = 177X + 199/ X + 1

178(X + 1) = 177X + 199

178X + 178 = 177X + 199

178X - 177X = 199 - 178

X = 21

Hence, Fred bowled 21 games to achieve an average of 178

Therefore, the score he needs to have on the 23rd game is obtained as:

= (23 × 183) - (22 × 178) = 4209 - 3916 = 293

Therefore, it is possible for Fred to raise his average from 178 to 183 in a single game, but he must bowl 293 in his next game to do this.

5 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

diamong [38]

Answer:

A-2, B-DNE*, C-3, D-DNE, E-4, F-1

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The first attachment shows the solutions to A and C.

The second attachment shows the solutions to E and F.

There are no real number solutions to systems B and D.

_____

In general, you can solve the linear equation for y, then substitute that into the quadratic. You can subtract the x-term on the left and complete the square to find the solutions.

A.

(3-x) +12 = x^2 +x

15 = x^2 + 2x

16 = x^2 +2x +1 = (x +1)^2 . . . . add the square of half the x-coefficient to complete the square; next take the square root

±4 -1 = x = {-5, 3) . . . . . identifies the second solution set for system A

__

B.

(x -1) -15 = x^2 +4x

-16 = x^2 +3x

-13.75 = x^2 +3x +2.25 = (x +1.5)^2

roots are complex: -1.5 ±i√13.75

__

C.

(1-2x) +5 = x^2 -3x

6 = x^2 -x

6.25 = x^2 -x + .25 = (x -.5)^2

±2.5 +.5 = x = {-2, 3} . . . . . identifies the third solution set for system C

__

remaining problems are done in a similar way.

_____

* DNE = does not exist. There is no matching solution set for the complex numbers that are the solutions to this.

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Hope this helps!

Brainliest would be great!

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With all care,

07x12!

4 0

3 years ago