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pogonyaev
3 years ago
6

4 lines extend from point E. A horizontal line extends to the left to point A and a vertical line extends up to point C. Another

line extends halfway between the other 2 lines to point B. Lines A E and E C form a right angle. Given that ∠CEA is a right angle and Ray E B bisects ∠CEA, which statement must be true? ∠BEA ≅ ∠CEA ∠CEB ≅ ∠CEA m∠CEB = 45° m∠CEA = 45°
Mathematics
2 answers:
bonufazy [111]3 years ago
5 0

Answer:

The answer is C. on edgen.

Step-by-step explanation:

C. ∠BEA ≅ ∠BEC

IceJOKER [234]3 years ago
3 0

Answer:

The answer is C

Step-by-step explanation:

:)

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33/7

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Find the circumference of a circle with the diameter of 10 inches. Leave your answers in form of pi
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Answer:

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3 years ago
A total of 150 new recruits join an army training course. After one month, 30 have dropped out. what is the percentage decrease
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So what will it be a percentage of? it will be the percentage of the original recruits, of the original 150.

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4 0
3 years ago
Read 2 more answers
What is the area of the figure shown?
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6 0
3 years ago
Read 2 more answers
1.    An AP has a common difference of 3.  Given that the nth term is 32, and the sum of the first n terms is 185, calculate the
netineya [11]

Answer:

The value of n is 10

Step-by-step explanation:

The formula of the nth term of the arithmetic progression is a_{n} = a + (n - 1)d

  • a is the first term
  • d is the common difference between each 2 consecutive terms
  • n is the position of the term

The formula of the sum of nth terms is S_{n} = \frac{n}{2} [2a + (n - 1)d]

∵ An AP has a common difference of 3

∴ d = 3

∵ The nth term is 32

∴ a_{n} = 32

→ Substitute them in the 1st rule above

∵ 32 = a + (n - 1)3

∴ 32 = a + 3(n) - 3(1)

∴ 32 = a + 3n - 3

→ Add 3 to both sides

∴ 35 = a + 3n

→ Switch the two sides

∴ a + 3n = 35

→ Subtract 3n from both sides

∴ a = 35 - 3n ⇒ (1)

∵ The sum of the first n terms is 185

∴ S_{n} = 185

→ Substitute the value of S_{n} and d in the 2nd rule above

∵ 185 = \frac{n}{2} [ 2a + (n - 1)3]

∴ 185 = \frac{n}{2} [2a + 3(n) - 3(1)]

∴ 185 = \frac{n}{2} [2a + 3n - 3]

→ Multiply both sides by 2

∴ 370 = n(2a + 3n - 3)

∴ 370 = 2an + 3n² - 3n

→ Substitute a by equation (1)

∴ 370 = 2n(35 - 3n) + 3n² - 3n

∴ 370 = 70n - 6n²+ 3n² - 3n

→ Add the like terms in the right side

∵ 370 = -3n² + 67n

→ Add 3n² to both sides

∴ 3n² + 370 = 67n

→ Subtract 67 from both sides

∴ 3n² - 67n + 370 = 0

→ Use your calculator to find n

∴ n = 10 and n = 37/3

∵ n must be a positive integer ⇒ 37/3 neglecting

∴ n = 10

∴ The value of n is 10

4 0
3 years ago
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