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Mademuasel [1]
2 years ago
10

Albert's house, Billy's house and the candy store form a triangle as shown below. If Albert's house is 3 miles from the candy st

ore, what is the range of values for the distance between Albert's house and Billy's house?

Mathematics
1 answer:
lora16 [44]2 years ago
8 0

5-3 < X < 3+5

Step-by-step explanation:

its a its just a a a a a a a

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758

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Jared bought a Suzuki 1000 for $12,698. If it depreciates at a rate of 11% per year, how much will it be worth in 3 years
Serga [27]
Original price = P = $12,698
Depreciation rate = r = 11% = 0.11
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The formula used will be:

A=P(1-r)^{t}

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A=12698(1-0.11)^{3}=8951.70

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2 years ago
Factorise completely 3m^2-48​
Helen [10]

Answer:

3 (m^2 - 16)

Step-by-step explanation:

factoring means taking out a common multiple of all the terms in the expression

in this case, if you multiply 3 and m^2, 3 and -16, you would get 3m^2-48​

so you take the three and put it outside of the parenthesis that contains the factored terms

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3 0
2 years ago
Which of the following statements is equivalent to 10x – 30?
Sergeeva-Olga [200]

Answer:

10(x-3)

Step-by-step explanation:

3 0
2 years ago
the length of a rectangle is 3 feet more than twice the width. if the width is increased by four feet the perimeter of the new r
densk [106]

Answer:

The area of the original rectangle  = 189 sq ft.

Step-by-step explanation:

Let, the width of the rectangle = m feet

So, the length of the rectangle =  (2 m + 3)  ft

Now, new width w'  = (m + 4)

Perimeter of new rectangle (P')   = 68 ft

Perimeter of a rectangle = 2 (LENGTH + WIDTH)

⇒68 ft   = 2( L + W')  

or, 68 ft   = 2 [( 2m + 3) + (m + 4)]

or, 2 (3m + 7)  = 68

or, 3m + 7 = 68/2  = 34

⇒ 3m = 34 - 7 = 27

⇒ m = 27/3 = 9

or, m = 9 ft

Hence, the original width  of the rectangle =  9 ft

Original Length of the rectangle = 2m  + 3  = 2(9) + 3 = 21 ft

Now, Area of the Rectangle = LENGTH X WIDTH

=  21 ft  x  9 ft  = 189 sq ft

Hence,the area of the original rectangle  = 189 sq ft.

5 0
3 years ago
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