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Sauron [17]
3 years ago
13

What is a angle called when two angles share a common side and a common vertex

Mathematics
2 answers:
sasho [114]3 years ago
5 0
They are called “Adjacent Angles”
bagirrra123 [75]3 years ago
3 0

Answer:

Adjacent Angles

Step-by-step explanation:

Adjacent angles are two angles that have a common vertex and a common side but do not overlap. They share the same vertex and the same common side.

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I have to turn this in, in 8 minutes please help​
FrozenT [24]

Answer:

20h+e

Step-by-step explanation:

e=$220

7 0
3 years ago
Help please math ..??
astraxan [27]

Answer:

(3, - 1)

Step-by-step explanation:

5x - 4y = -11

2x + 3y = -9

Multiply the top equation by 2 and the bottom equation by - 5 to cancel out the x's.

10x - 8y = - 22

- 10x - 15y = 45

Cancel out x's.

-8y = - 22

- 15y = 45

Add like terms.

- 23y = 23

Can't have a negative variable to flip them.

-23 = 23y

Divide.

y = - 1

Input y into one of the equations and solve for x.

2x + 3(-1) = -9

Simplify.

2x -3 = -9

Cancel out -3 by adding 3.

2x = -6

Divide.

x - -3

8 0
3 years ago
Brainliest help please
anzhelika [568]

Answer:

9x5=45 D is ur answer

Step-by-step explanation:

brainliest???

7 0
2 years ago
Read 2 more answers
Find gradient <br><br>xe^y + 4 ln y = x² at (1, 1)​
cricket20 [7]

xe^y+4\ln y=x^2

Differentiate both sides with respect to <em>x</em>, assuming <em>y</em> = <em>y</em>(<em>x</em>).

\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}

\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x

\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x

Solve for d<em>y</em>/d<em>x</em> :

e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x

\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}

If <em>y</em> ≠ 0, we can write

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}

At the point (1, 1), the derivative is

\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}

4 0
3 years ago
What fraction is equivalent to 1/8??
ASHA 777 [7]

Answer:

2/16

5/40

Step-by-step explanation:

4 0
3 years ago
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