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3 years ago

What is a angle called when two angles share a common side and a common vertex

Mathematics

2 answers:

sasho [114]3 years ago

5 0

They are called “Adjacent Angles”

bagirrra123 [75]3 years ago

3 0

Answer:

Adjacent Angles

Step-by-step explanation:

Adjacent angles are two angles that have a common vertex and a common side but do not overlap. They share the same vertex and the same common side.

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I have to turn this in, in 8 minutes please help

FrozenT [24]

Answer:

20h+e

Step-by-step explanation:

e=$220

7 0

3 years ago

Help please math ..??

astraxan [27]

Answer:

(3, - 1)

Step-by-step explanation:

5x - 4y = -11

2x + 3y = -9

Multiply the top equation by 2 and the bottom equation by - 5 to cancel out the x's.

10x - 8y = - 22

- 10x - 15y = 45

Cancel out x's.

-8y = - 22

- 15y = 45

Add like terms.

- 23y = 23

Can't have a negative variable to flip them.

-23 = 23y

Divide.

y = - 1

Input y into one of the equations and solve for x.

2x + 3(-1) = -9

Simplify.

2x -3 = -9

Cancel out -3 by adding 3.

2x = -6

Divide.

x - -3

8 0

3 years ago

Brainliest help please

anzhelika [568]

Answer:

9x5=45 D is ur answer

Step-by-step explanation:

brainliest???

7 0

2 years ago

Read 2 more answers

Find gradient xe^y + 4 ln y = x² at (1, 1)

cricket20 [7]

$xe^y+4\ln y=x^2$

Differentiate both sides with respect to x, assuming y = y(x).

$\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}$

$\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x$

$\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

$e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

Solve for dy/dx :

$e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x$

$\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}$

If y ≠ 0, we can write

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}$

At the point (1, 1), the derivative is

$\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}$

4 0

3 years ago

What fraction is equivalent to 1/8??

ASHA 777 [7]

Answer:

2/16

5/40

Step-by-step explanation:

4 0

3 years ago