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charle [14.2K]
3 years ago
10

Zoe was given a box of assorted chocolates for her birthday. Each night, Zoe treated herself to some chocolates. Zoe ate 4 choco

lates each night and after 3 nights, there were 12 chocolates remaining in the box. Write an equation for C,C, in terms of t,t, representing the number of chocolates remaining in the box tt days after Zoe's birthday.
Mathematics
2 answers:
Olenka [21]3 years ago
8 0

Answer:

C = -4t + 24

Step-by-step explanation:

Alex Ar [27]3 years ago
6 0

Answer:

4 time 3 eqauls 12 plus 12 eqauls 24

Step-by-step explanation:

You might be interested in
The diameter of a human red blood cell is 0.000009 m The diameter of a cold virus is 0.00000003 m. Approximately how many times
Lera25 [3.4K]

Answer:

Red Cell is 300 times larger than the virus

Step-by-step explanation:

Size in scientific Notation

  • Red Cell = 9 * 10^-6
  • Virus = 9 * 10^-8

Procedure.

  • Count the number of zeros in the decimal
  • Red Cell = 5 ; virus = 7
  • And one more to each
  • Red Cell = 6; virus = 7
  • change the numbers to minus
  • Red Cell = -6 ; virus = - 7
  • The last row is the powers as shown above.

Answer

9*10^-6/3 * 10^-8

3*10^(-6 - - 8)

3*10^(-  6 + 8)

3^10^2 or 300 times larger

4 0
3 years ago
Read 2 more answers
In the diagram m angle ACB = 61<br> Find m angle BCD
Marina86 [1]

we are given that

angle(ACF)=90

angle(ACB)=61

sum of all angles along any line is 180

so, we get

angle(ACF)+angle(ACD)=180

we can plug value

90+angle(ACD)=180

angle(ACD)=90

now, we can use formula

angle(ACD)=angle(ACB)+angle(BCD)

now, we can plug values

and we get

90=61+angle(BCD)

90-61=61-61+angle(BCD)

angle(BCD)=29................Answer


7 0
3 years ago
Read 2 more answers
If the cos of angle x is 8 over 17 and the triangle was dilated to be two times as big as the original, what would be the value
Viktor [21]

Answer:

the answer is 8/17

Step-by-step explanation:

i got it right on the quiz

6 0
3 years ago
Find all real solutions to the equation (x² − 6x +3)(2x² − 4x − 7) = 0.
Jet001 [13]

Answer:

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ;  x = \frac{2-(3)\sqrt{2}}{2}

Step-by-step explanation:

Relation given in the question:

(x² − 6x +3)(2x² − 4x − 7) = 0

Now,

for the above relation to be true the  following condition must be followed:

Either  (x² − 6x +3) = 0 ............(1)

or

(2x² − 4x − 7) = 0 ..........(2)

now considering the equation (1)

(x² − 6x +3) = 0

the roots can be found out as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

for the equation ax² + bx + c = 0

thus,

the roots are

x = \frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times(3)}}{2\times(1)}

or

x = \frac{6\pm\sqrt{36-12}}{2}

or

x = \frac{6+\sqrt{24}}{2} and, x = x = \frac{6-\sqrt{24}}{2}

or

x = \frac{6+2\sqrt{6}}{2} and, x = x = \frac{6-2\sqrt{6}}{2}

or

x = 3 + √6 and x = 3 - √6

similarly for (2x² − 4x − 7) = 0.

we have

the roots are

x = \frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-7)}}{2\times(2)}

or

x = \frac{4\pm\sqrt{16+56}}{4}

or

x = \frac{4+\sqrt{72}}{4} and, x = x = \frac{4-\sqrt{72}}{4}

or

x = \frac{4+\sqrt{2^2\times3^2\times2}}{2} and, x = x = \frac{4-\sqrt{2^2\times3^2\times2}}{4}

or

x = \frac{4+(2\times3)\sqrt{2}}{2} and, x = x = \frac{4-(2\times3)\sqrt{2}}{4}

or

x = \frac{2+3\sqrt{2}}{2} and, x = \frac{2-(3)\sqrt{2}}{2}

Hence, the possible roots are

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ; x = \frac{2-(3)\sqrt{2}}{2}

7 0
3 years ago
Evaluate the piecewise function for the given values.
adoni [48]

Answer:

f(-3) = -2

f(-2.6) = -2

f(0.6) = 2.4

f(4.5) = 8.5

Step-by-step explanation:

(Whole question:

Evaluate the piecewise function for the given values.

Find f(-3), f(-2,6), f(0.6), and f(4.5) for f(x)={ -2 If x ≤ 0 4x. If 0 <x <1. x + 4. If x ≥ 1)

As the piecewise function shows, the function f(x) has the value of -2 for values of x lesser or equal than 0, has the value of 4x if the value of x is between 0 and 1, and has the value of x+4 for values of x greater or equal than 1.

So, for f(-3), the value of x is lesser than 0, so we have that f(-3) = -2

For f(-2.6), the value of x is lesser than 0, so we have that f(-3) = -2

For f(0.6), the value of x is between 0 and 1, so we have that f(0.6) = 4*0.6 = 2.4

For f(4.5), the value of x is greater than 1, so we have that f(4.5) = 4.5 + 4 = 8.5

5 0
3 years ago
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