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Leya [2.2K]
3 years ago
6

The diameter of a human red blood cell is 0.000009 m The diameter of a cold virus is 0.00000003 m. Approximately how many times

as large is the diameter of a red blood cell as the diameter of a cold virus?
Mathematics
2 answers:
Lera25 [3.4K]3 years ago
4 0

Answer:

Red Cell is 300 times larger than the virus

Step-by-step explanation:

Size in scientific Notation

  • Red Cell = 9 * 10^-6
  • Virus = 9 * 10^-8

Procedure.

  • Count the number of zeros in the decimal
  • Red Cell = 5 ; virus = 7
  • And one more to each
  • Red Cell = 6; virus = 7
  • change the numbers to minus
  • Red Cell = -6 ; virus = - 7
  • The last row is the powers as shown above.

Answer

9*10^-6/3 * 10^-8

3*10^(-6 - - 8)

3*10^(-  6 + 8)

3^10^2 or 300 times larger

Hitman42 [59]3 years ago
4 0

Answer:

3*10^2

Step-by-step explanation:

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When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let
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Answer:

(a) 0.873 (b) 0.007 (c) 0.715 (d) 0.277 (e) 1.25 and 1.09

Step-by-step explanation:

The probability that the random variable X takes the value x is given by P(X=x) = 25Cx 0.05^x0.95^{25-x}. Then,

(a) P(X\leq) = (25C0)(0.05^0)(0.95^{25}) + (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23})=  0.873

(b) P(X\geq5) = 1-P(X\leq4) = 1 - (0.873 + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21})) = 1 - (0.873 + 0.12) = 0.007

(c) P(1\leqX\leq4) = (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23}) + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21}) = 0.715

(d) P(X=0) = (25C0)(0.05^0)(0.95^{25}) = 0.277  

(e) E(X) = np = (25)(0.05) = 1.25 and Sd(X) = \sqrt{Var(X)} = \sqrt{np(1-p)} = 1.09

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