The problem ask to calculate the initial speed of the sled that was shove up a frictionless 28 degree incline and reaches a maximum vertical height of 1.35 m than it started and the initial speed of the sled is 5.14 m/s. I hope you are satisified with my answer
The perimeter is:
P = 2x + 2y = 80
The area is:
A = x * y
The area as a function of a variable is:
A (x) = x * (40-x)
Rewriting we have:
A (x) = 40x-x ^ 2
We derive the function:
A '(x) = 40-2x
We equal zero and clear x:
40-2x = 0
2x = 40
x = 40/2
x = 20 feet
The other dimension is:
y = 40 - x
y = 40 - 20
y = 20 feet
The area will be:
A = x * y
A = 20 * 20
A = 400 feet ^ 2
Answer:
The dimensions are:
x = 20 feet
y = 20 feet
The area is:
A = 400 feet ^ 2
456- 12= 444
37×12= 444
=12
I think the answer is 60 and 30 but I'm on break so I'm not thinking rn
Answer:
x = -4, y = -2
Step-by-step explanation:
substitute for y
2x - 5(x + 2) = 2
distribute -5
2x -5x - 10 = 2
solve
-3x - 10 = 2
add 10 on both sides
-3x = 12
divide by -3
x = -4
now substitute for x in the equation y = x + 2
y = -4 + 2
y = -2
