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Oksana_A [137]
3 years ago
5

The product of an irrational number and a rational number will be

Mathematics
1 answer:
BigorU [14]3 years ago
4 0

Answer:

an irrational number

Step-by-step explanation:

You might be interested in
Which of the following is a solution of y - x < -3?
Mariulka [41]

Answer:

Option A. (6,2)

Step-by-step explanation:

We have the following inequality:

y- x

Solving for y we have:

y

The line that limits the region of inequality is

y = x-3

Then the region of inequality are all values of y that are less than f (x) = x-3

In other words, the points belonging to the inequality are all those that lie below the line.

To find out which point belongs to this region substitute inequality and observe if it is satisfied

A. (6,2)

2

2   <em> is satisfied</em>

B. (2, 6)

6

6   <em>it is not satisfied</em>

C. (2, -1)

-1

-1 it is not satisfied

<em>The answer is the option A</em>

4 0
3 years ago
Mika opened a bank account that earns simple interest with an initial deposit of $2,200.
VashaNatasha [74]

Answer:2.75

Step-by-step explanation:

4 0
3 years ago
Evaluate the series
dalvyx [7]

Answer:

the value of the series;

\sum_{k=1}^{6}(25-k^2) = 59

C) 59

Step-by-step explanation:

Recall that;

\sum_{1}^{n}a_n = a_1+a_2+...+a_n\\

Therefore, we can evaluate the series;

\sum_{k=1}^{6}(25-k^2)

by summing the values of the series within that interval.

the values of the series are evaluated by substituting the corresponding values of k into the equation.

\sum_{k=1}^{6}(25-k^2) =(25-1^2)+(25-2^2)+(25-3^2)+(25-4^2)+(25-5^2)+(25-6^2)\\\sum_{k=1}^{6}(25-k^2) =(25-1)+(25-4)+(25-9)+(25-16)+(25-25)+(25-36)\\\sum_{k=1}^{6}(25-k^2) =24+21+16+9+0+(-11)\\\sum_{k=1}^{6}(25-k^2) = 59\\

So, the value of the series;

\sum_{k=1}^{6}(25-k^2) = 59

6 0
3 years ago
Can someone help me plz
katen-ka-za [31]

Answer:

I would choose c

Step -by- step explanation:

When you work out 4 oranges and 4 apples divided by 10 youll get 2 and a makes it a loss and also when you work out b its still a loss and there is a solution to the problem so it has to be c in my opinion.

3 0
3 years ago
Solve for x, <br> 3(x – 4) ≥ 5x + 2
Flauer [41]

\Large\textsc{answer :}

x≤-7

\Large\textsc{calculations :}

First , use the distributive property :

3(x-4)≥5x+2

3x-12≥5x+2

Subtract 5x on both sides :

3x-5x-12≥2

Now , add 12 on both sides :

3x-5x≥2+12

3x-5x≥14

Subtract the x's :

-2x≥14

Divide by -2 on both sides and watch what happens :

x≤-7 (notice that the inequality sign changed from "greater than or equal to" to "less than or equal to")

If we divide both sides of an inequality by a negative number , we change the inequality sign .

\footnotesize\textit{hope helpful~}

7 0
2 years ago
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