Can someone help me with this question please
1 answer:
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Let
x--------> original length side of a square
we know that
area rectangle=length*width
area=126 in²
length=(x+8)
width=(x-3)
so
126=(x+8)*(x-3)------> x²-3x+8x-24=126----> x²+5x-150=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solution is
x=10 in
the answer is
the original length side of a square is 10 in
x--------> original length side of a square
we know that
area rectangle=length*width
area=126 in²
length=(x+8)
width=(x-3)
so
126=(x+8)*(x-3)------> x²-3x+8x-24=126----> x²+5x-150=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solution is
x=10 in
the answer is
the original length side of a square is 10 in