CAN SOMEONE HELP ME WITH MY HW? PLEASE

Mathematics

2 answers:

Dafna1 [17]2 years ago

6 0

Can we get a clearer pic?

steposvetlana [31]2 years ago

4 0

I CANNOT SEE THAT MY GUY

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A graph is constructed such that time (in hours)is the x-variable and distance (in miles) is the y-variable. If you plot the dis

astra-53 [7]

For every one mile (across) the line will go up 60. This line (from (0,0) ) is therefore y = 60x
:D

8 0

3 years ago

Find the equation of the line perpendicularly to y=3x - 6 that runs through the point (-1, -3), need help ASAP

mr_godi [17]

Answer:

y = 1/3x - 10/3

Step-by-step explanation:

Perpendicular lines have slopes that are negative reciprocals of one another so m = -1/3

Given (-1,-3)

y = mx + b

-3 = -1/3(-1) + b

-9/3 = 1/3 + b

b = -10/3

so y = 1/3x - 10/3

3 0

2 years ago

Solve for c. ! PLEASE SOLVE !

Strike441 [17]

theres no real way to solve that because of B have you asked one else about this question you cant solve this with a expression.

3 0

3 years ago

Use polynomial long division to rewrite the following fraction in the form q(x)+r(x)d(x), where d(x) is the denominator of the o

SOVA2 [1]

Step-by-step explanation:

p(x) = 2x^2+8x-12

d(x) = x + 1

r(x) = -13

q(x) = 2x + 6

$\\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2x +6 \\ x + 1 \sqrt{ {2x}^{2} + 8x - 12} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: {2x}^{2} + 2x \\ \: \: \: \: \: \: \: \: \: \: \: \frac{ \: - \: \: \: \: \: \: - \: \: \: \: \: }{} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 6x - 12 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 6x + 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{ - \: \: - \: \: \: \: \: }{} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - 13$