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Norma-Jean [14]
3 years ago
10

Given: triangle ABC, D is on AC, m

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
8 0

Answer:

Step-by-step explanation:

B

slavikrds [6]3 years ago
3 0
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Claudia is reading a book that has 360 pages. she read some of the book last week. she plans to read 46 pages. when she does, sh
gladu [14]
She read 242 pages. I got that by finding what (4/5) x (360) was which is 288 and then subtracted 46 to see what was left over which is 242
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3 years ago
PLS HELP TIMED QUIZ The size of a television screen is given as the length of the diagonal. If a television is advertised as hav
grin007 [14]

Answer:

D.24

Pythagorean states:

hypotenuse^2 = side1^2 + side2^2

30^2 = 18^2 + side2^2

side2^2 = 30^2 - 18^2

side2^2 = 900 - 324

side2^2 = 576

side2 = sqr root 576

side2 = 24

Source: http://www.1728.org/pythgorn.htm

Step-by-step explanation:

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3 years ago
In a random sample of 85 people attending a workshop, 63 of the respondents said the workshop was useful. What is the sample pro
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Divide the number of respondents saying it was useful by the total number
63/85 = 0.74
8 0
3 years ago
Read 2 more answers
Paige launched a ball using a catapult she built. The height of the ball (in meters above the ground) ttt seconds after launch i
agasfer [191]

Answer:

1) Factor form : h(t)=-5t(t-8)

2) 8 second after launch.

Step-by-step explanation:

The height of the ball (in meters above the ground) t seconds after launch is modeled by

h(t)=-5t^2+40t

To find the time when ball hit the ground, we need to find the factor form of the given function.

h(t)=-5t(t-8)

When ball hi the ground, then height of the ball from the ground is 0.

h(t)=0

-5t(t-8)=0

Using zero product property, we get

-5t=0\Rightarrow t=0

t-8=0\Rightarrow t=8

Ball hit the ground at t=0 and t=8. It means ball hit the ground in starting and 8 second after launch.

5 0
3 years ago
The velocity,v of a missile is related to time t, By the equation v=5t^2+3t+1.calculate the time at which the velocity is minimu
Cloud [144]

Answer:

  • time: t = -0.3
  • minimum: v = 0.55

Step-by-step explanation:

For quadratic ax^2 + bx + c, the extreme value is found at x=-b/(2a). For your quadratic, the minimum is found at ...

  t = -(3)/(2(5))

  t = -0.3 . . . . . time of minimum velocity

__

The value of velocity at that time is ...

  v = 5(-0.3)^2 +3(-0.3) +1 = 5(.09) -.9 +1

  v = 0.55 . . . . . value of minimum velocity

3 0
3 years ago
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