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tankabanditka [31]
2 years ago
13

First come first served brainiest:) do it right

Mathematics
1 answer:
Arte-miy333 [17]2 years ago
3 0

To Be Honest I Dont Know

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Answer:

By shortening

Step-by-step explanation:

1. 5x>35 /5

x>5

2. 4x<8y+12 /4

x<2y+3



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David uses 1/4 bag of potting soil to plant 6 tomato plants. If he uses the same amount of potting soil for each plant, what fra
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Step-by-step explanation:

A

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The sign of each Y coordinate changed
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Please help!!! I don’t understand it at all and I need it ASAP!
Ivenika [448]

9514 1404 393

Answer:

  \textbf{D.}\quad g(x)=\sqrt{x+6}+4

Step-by-step explanation:

A lot of math is about matching patterns.

For example, ...

  g(x) = f(x -h) +k

means g(x) is the function f(x) translated right by h units and up by k units. This will be true for any expression of f(x).

__

In this problem, f(x) = √x. We want to translate it left 6 units (h=-6)*, and up 4 units (k=4).

The notation above means that we will replace x with (x-h) = x+6. and we will add k = 4 to the result.

  f(x) = √x

  g(x) = f(x+6) +4

  g(x) = √(x+6) +4 . . . . . . matches choice D

_____

* Left is the opposite of right, so left 6 units is the opposite of right 6 units. h=6 for <em>right 6 units</em>, so h=-6 for <em>left 6 units</em>. Then x-h = x-(-6) = x+6.

__

<em>Comment on the graph</em>

I find it useful to see a picture with these things. In the attached graphing calculator output, the blue curve is left 6 and up 4 from the red curve. The blue curve is g(x); the red one is f(x).

7 0
3 years ago
How do you graph -1/5x-1 and 4/5x-6
kakasveta [241]

Answer:

The points for the given to linear equations is (5 , - 2) and (5 , - 1)

The points is plotted on the graph shown .

Step-by-step explanation:

Given as :

The two linear equation are

y = \dfrac{-1}{5}x - 1                  ...........1

y = \dfrac{4}{5}x - 6                  ...........2

Now, Solving both the linear equations

Put the value of y from eq 2 into eq 1

I.e  \dfrac{4}{5}x - 6 = \dfrac{-1}{5}x - 1

Or, \dfrac{4}{5}x + \dfrac{1}{5}x  = 6 - 1

Or,  \dfrac{4 + 1}{5}x = 5

or, \dfrac{5}{5}x = 5

∴ x = 5

Now, Put the value of x in eq 1

So, y = \dfrac{-1}{5}x - 1      

Or, y = \dfrac{-1}{5}× 5 - 1              

or,  y = \dfrac{-5}{5} - 1

Or, y = - 1 - 1

I.e y = -2

So, For x = 5 , y = - 2

Point is (x_1 , y_1) = (5 , - 2)

Again , put the value of x in eq 2

So, y = \dfrac{4}{5}x - 6

Or, y = \dfrac{4}{5}× 5 - 6

Or, y = \frac{4\times 5}{5} - 6

Or, y = 4 - 6

I.e y = - 2

So, For x = 5 , y = - 2

Point is (x_2 , y_2) = (5 , - 2)

Hence, The points for the given to linear equations is (5 , - 2) and (5 , - 2)

The points is plotted on the graph shown . Answer

5 0
3 years ago
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