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skad [1K]
3 years ago
6

What is the approximate area of the circle shown below?

Mathematics
2 answers:
Yuri [45]3 years ago
8 0

Answer:

I sthink is a

Step-by-step explanation:

jeka57 [31]3 years ago
6 0

Step-by-step explanation:

Formula :

\boxed{A = \pi r^2}

A = 3.14 × 9.4²

A = 3.14 × (9.4 × 9.4)

A = 3.14 × 88.36

A = 277.45 cm²

A = <u>2</u><u>7</u><u>8</u><u> </u><u>cm²</u> (rounded to the nearest unit)

So, the approximate area of the circle shown below is 278 cm² (A)

#CMIIW

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A new bridge structure requires triangles that are in a ratio of 1:1. If AC = 5x − 5 and EC = 3x + 9, find the distance between
Montano1993 [528]

Answer:

C. 60 ft

Step-by-step explanation:

If triangles ABC and EDC are in a 1:1 relation, they are congruent, and  

    AC = EC

5x - 5 = 3x + 9

    5x = 3x + 14

    2x = 14

      x = 7

AC = 5x + 5 = 5(7) - 5 = 35 - 5 = 30 ft

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5 0
3 years ago
Read 2 more answers
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AlekseyPX

> and < with the lines under it mean that they can also be equal to the constant on the other side (greater/less than or equal to)

So x <= 3 can be anything less than 3 and 3.

*the = in this inequality is the equivalent of a line

Now vice versa.

x => 3 can be anything greater than 3 and 3.

Now for the dots.

The open dots in signs are (< and >).

Basically they start at that point they are on but don't include it.

So an open dot at 3 pointing to the left means that the value is greater than 3 but does not include 3.

The closed dots in signs are (<= and =>).

They start at the point and include it.

So a closed dot a 3 pointing to the left means that the value is greater than 3 and includes 3.

Arrows.

Arrows pointing to the left mean that the values are getting bigger.

Arrows pointing to the right mean that the values are getting smaller.

ie : An arrow pointing to the left with a starting point at 3 = 3 and anything bigger, such as 4.

ie : An arrow pointing to the right with a starting point at 3 = 3 and anything smaller, such as 2.

Solve for problems.

The main concept is isolate the variable.

This basically means make the variable be lonely ^^

Use +, -, *, and /

Ex : 6x + 2 > 3

First, we would subtract 2 from both sides.

6x > 1

Then, we would divide each side by 6, leaving the x alone.

x > 1/6

And voila! x is anything greater than 1/6 but it does not include 1/6.

Hope this helps! ^^

8 0
3 years ago
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