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Zepler [3.9K]
3 years ago
10

2/9n + 1/2 = 2/3(n+3) what does n equal?

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
7 0
\dfrac{2}{9}n+\dfrac{1}{2}=\dfrac{2}{3}(n+3)\ \ \ \ \ |multiply\ both\ sides\ by\ 18\\\\2\cdot2n+9=6\cdot2(n+3)\\\\4n+9=12(n+3)\\\\4n+9=12n+36\ \ \ \ |subtract\ 9\ from\ both\ sides\\\\4n=12n+27\ \ \ \ |subtract\ 12n\ from\ both\ sides\\\\-8n=27\ \ \ \ \ |divide\ both\ sides\ by\ (-8)\\\\n=-\dfrac{27}{8}\\\\n=-3\dfrac{3}{8}
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Charra [1.4K]
To solve equations, you want to isolate the X. So, the first step will be to distribute that 4 into the 2x + 1. 
4 x 2 = 8
4 x 1 = 4              So we have 4(2x+1) = 8x+4. When we plug this into the equation, that gets us 8x + 4 - 2x = -8. Next, let's combine like terms now that we've distributed everything out. 8x - 2x = 6x. Now we have
6x + 4 = -8. Next, we subtract 4 from both sides to isolate the X;              6x = -8 - 4. -8 - 4  = -12. So now we have 6x = -12. The final step to isolating the X is to divide both sides by 6; 6/6 = 1, and -12/6 = -2. Our final answer is X = -2. 
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Mademuasel [1]
The correct answer is:  [B]:  "40 yd² " .
_____________________________________________________
First, find the area of the triangle:

The formula of the area of a triangle, "A":

A = (1/2) * b * h ; 

in which:  " A = area (in units 'squared') ;  in our case, " yd² " ; 

                 " b = base length" = 6 yd.  

                 " h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
___________________________________________________
→  A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ; 
                                                                 
                                                                   =  " 24 yd² " .
___________________________________________________
Now, find the area, "A", of the square:

The formula for the area, "A" of a square:

   A = s² ;

in which:  "A = area (in "units squared") ; in our case, " yd² " ;
                 
                 "s = side length (since a 'square' has all FOUR (4) equal side lengths);

 A = s²  = (4 yd)² = 4² * yd² =  "16 yd² "
_________________________________________________
Now, we add the areas of BOTH the triangle AND the square:
_________________________________________________
        →  " 24 yd²  +  16 yd² " ; 

to get:  " 40 yd² " ;  which is:  Answer choice:  [B]:  " 40 yd² " .
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mars1129 [50]

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Answer:

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