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Leni [432]
3 years ago
8

How do you find the area of a circle with only the height

Mathematics
1 answer:
ASHA 777 [7]3 years ago
8 0

Answer:

in geometry, a circle is the curve that forms the boundary of a disc. Curves, like lines, have zero width and thus zero area.

For some reason, this very simple thing doesn’t seem to be taught much - I certainly recall my maths teachers referring to the area of a circle instead of the area of a disc!

As you haven’t mentioned the radius of the circle, let us consider a generic circle of radius r, thus we want to find the height of a triangle whose area is πr².

Step-by-step explanation:

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Instructions: Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Morgarella [4.7K]

Answer:

y = 3x - 13................slope= 3, point= (5,2)

y = 3x + 11.................slope= 3, point= (2,17)

3y = x + 11................slope= 1/3, point= (-5,2)

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Step-by-step explanation:

To match each equation to its slope and point, remember that an equation in y = mx + b has slope m. The point must also satisfy or make true the equation when substituted for (x,y).

y=3x-13  has slope 3. The point (2,17) make it false. But (5,2) makes it true.

17 = 3(2) - 13                 2 = 3(5) - 13

17 = 6-13                       2 = 15 - 13

17 = - 7  False              2 = 2 True

y=3x+11  has slope 3. This means (2,17) must be true.

3y=x+11  can be converted to y = 1/3x + 11/3. It has slope 1/3. Test each point.

2= 1/3(19) + 11/3                 -2 = 1/3(17) + 11/3        2 = 1/3(-5) + 11/3

2 = 19/3 + 11/3                    -2 = 17/3 + 11/3          2 = -5/3 + 11/3

False                                    False                        2 = 6/3    True

3y=x-13 can be converted to y = 1/3x - 13/3. It has slope 1/3. Test each remaining point.

2= 1/3(19) - 13/3                 -2 = 1/3(17) - 13/3        

2 = 19/3 - 13/3                    -2 = 17/3 - 13/3          

2 = 6/3                                -2 = 4/3

True                                   False                        

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