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2 years ago

Bonsoir pour vais vous m'aider svp développer et réduire l'expression D=(2x+3)²-(x+4)² et factoriser D Svp aider moi

Mathematics

1 answer:

GalinKa [24]2 years ago

5 0

Answer:

d = 3x²+ 4x - 7

C'est la réponse j'espère que ça aide.

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What are the x– and y–intercepts of the graph of y = 2x^2 – 8x – 10?

Nadya [2.5K]

x-intercepts are found by setting y=0
$y=2x^2-8x-10\rightarrow0=2x^2-8x-10$
factor out a 2 $0=2(x^2-4x-5)\rightarrow0=x^2-4x-5$
 $0=(x-5)(x+1)$ roots should be x=-1,5
therefore, x-intercepts are (-1,0) and (5,0)

y-intercepts are found by setting x=0
$y=2x^2-8x-10\rightarrow y=2(0)^2-8(0)-10$
$\rightarrow y=0-0-10=-10$
therefore, y-intercept is (0,-10)

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3 years ago

Help me find the numbers for the function table

mamaluj [8]

Answer:

0,4,7

Step-by-step explanation:

you take the input number like 8 subtract it by 4 to get the output

5 0

2 years ago

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Please give me the correct answer.

nydimaria [60]

Answer:

The third one which is the one on the bottom to the right under 34 the ont he bottom

7 0

2 years ago

How do I find the vertex and the standard form? Plz explain

xenn [34]

Answer:

Vertex form

y = -4(x + 3)^2 + 10

Standard form;

y = -4x^2-24x - 26

Step-by-step explanation:

Mathematically, we have the vertex form as

y = a(x-h)^2 + k

(h,k) represents the vertex

We have h as -3 and k as 10

y = a(x+3)^2 + 10

To get a, we substitute any of the points

Let us use (-1,-6)

-6 = a(-1+3)^2 + 10

-6-10 = 4a

4a = -16

a = -16/4

a = -4

So we have the equation as;

y = -4(x+3)^2 + 10

For the standard form;

We expand the vertex form;

y = -4(x + 3)(x + 3) + 10

y = -4(x^2 + 6x + 9) + 10

y = -4x^2 - 24x -36 + 10

y = -4x^2 -24x -26

7 0

2 years ago

Which statement is true regarding the graphed functions?

Vladimir79 [104]

let's analyze each case to determine the solution

case 1) f(0) = 2 and g(–2) = 0

For x=0-----> find the value of f(0) in the graph-----> f(0)=4

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

the statement of the case 1) is false

case 2) f(0) = 4 and g(–2) = 4

For x=0-----> find the value of f(0) in the graph-----> f(0)=4

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

the statement of the case 2) is false

case 3) f(2) = 0 and g(–2) = 0

For x=2-----> find the value of f(2) in the graph-----> f(2)=0

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

the statement of the case 3) is true

case 4) f(–2) = 0 and g(–2) = 0

For x=-2-----> find the value of f(-2) in the graph-----> f(-2) is greater than 12

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

the statement of the case 4) is false

therefore

the answer is

f(2) = 0 and g(–2) = 0-------> this statement is true

6 0

3 years ago

Read 2 more answers