This question can be solved primarily by L'Hospital Rule and the Product Rule.
I) Product Rule and L'Hospital Rule:
![y= \lim_{x \to 0} \frac{[2xcos(x)-x^2sin(x)]-2sin(x)cos(x)}{4x^3}](https://tex.z-dn.net/?f=y%3D%20%5Clim_%7Bx%20%5Cto%200%7D%20%5Cfrac%7B%5B2xcos%28x%29-x%5E2sin%28x%29%5D-2sin%28x%29cos%28x%29%7D%7B4x%5E3%7D%20)
II) Product Rule and L'Hospital Rule:
![y= \lim_{x \to 0} \frac{[-2xsin(x)+2cos(x)]-[2xsin(x)+x^2cos(x)]-[2cos^2(x)-2sin^2(x)]}{12x^2} \\ y= \lim_{x \to 0} \frac{2cos(x)-4xsin(x)-x^2cos(x)-2cos^2(x)+2sin^2(x)}{12x^2}](https://tex.z-dn.net/?f=y%3D%20%5Clim_%7Bx%20%5Cto%200%7D%20%5Cfrac%7B%5B-2xsin%28x%29%2B2cos%28x%29%5D-%5B2xsin%28x%29%2Bx%5E2cos%28x%29%5D-%5B2cos%5E2%28x%29-2sin%5E2%28x%29%5D%7D%7B12x%5E2%7D%20%5C%5C%20y%3D%20%5Clim_%7Bx%20%5Cto%200%7D%20%5Cfrac%7B2cos%28x%29-4xsin%28x%29-x%5E2cos%28x%29-2cos%5E2%28x%29%2B2sin%5E2%28x%29%7D%7B12x%5E2%7D)
III) Product Rule and L'Hospital Rule:
![]y= \alpha + \beta \\ \\ \alpha =\lim_{x \to 0} \frac{-2sin(x)-[4sin(x)+4xcos(x)]-[2xcos(x)-x^2sin(x)]}{24x} \\ \beta = \lim_{x \to 0} \frac{4sin(x)cos(x)+4sin(x)cos(x)}{24x} \\ \\ y = \lim_{x \to 0} \frac{-6sin(x)-4xcos(x)-2xcos(x)+x^2sin(x)+8sin(x)cos(x)}{24x}](https://tex.z-dn.net/?f=%5Dy%3D%20%5Calpha%20%2B%20%5Cbeta%20%5C%5C%20%5C%5C%20%5Calpha%20%3D%5Clim_%7Bx%20%5Cto%200%7D%20%5Cfrac%7B-2sin%28x%29-%5B4sin%28x%29%2B4xcos%28x%29%5D-%5B2xcos%28x%29-x%5E2sin%28x%29%5D%7D%7B24x%7D%20%5C%5C%20%5Cbeta%20%3D%20%5Clim_%7Bx%20%5Cto%200%7D%20%5Cfrac%7B4sin%28x%29cos%28x%29%2B4sin%28x%29cos%28x%29%7D%7B24x%7D%20%5C%5C%20%20%5C%5C%20y%20%3D%20%5Clim_%7Bx%20%5Cto%200%7D%20%5Cfrac%7B-6sin%28x%29-4xcos%28x%29-2xcos%28x%29%2Bx%5E2sin%28x%29%2B8sin%28x%29cos%28x%29%7D%7B24x%7D)
IV) Product Rule and L'Hospital Rule:
![y = \phi + \varphi \\ \\ \phi = \lim_{x \to 0} \frac{-6cos(x)-[-4xsin(x)+4cos(x)]-[2cos(x)-2xsin(x)]}{24x} \\ \varphi = \lim_{x \to 0} \frac{[2xsin(x)+x^2cos(x)]+[8cos^2(x)-8sin(x)]}{24x}](https://tex.z-dn.net/?f=y%20%3D%20%5Cphi%20%2B%20%5Cvarphi%20%5C%5C%20%20%5C%5C%20%5Cphi%20%3D%20%5Clim_%7Bx%20%5Cto%200%7D%20%20%5Cfrac%7B-6cos%28x%29-%5B-4xsin%28x%29%2B4cos%28x%29%5D-%5B2cos%28x%29-2xsin%28x%29%5D%7D%7B24x%7D%20%20%5C%5C%20%5Cvarphi%20%3D%20%5Clim_%7Bx%20%5Cto%200%7D%20%20%5Cfrac%7B%5B2xsin%28x%29%2Bx%5E2cos%28x%29%5D%2B%5B8cos%5E2%28x%29-8sin%28x%29%5D%7D%7B24x%7D%20)
V) Using the Definition of Limit:
Answer:
4y
Step-by-step explanation:
every part of the equation can be evenly divided by 4 and y
so this leaves you with 4y (-4
+ 3y - 1)
Answer:
A
-2 < x ≤ 3 (All x values between -2 and 3; excluding -2 and including 3)
Step-by-step explanation:
I feel the answer is A because from what we know, domain is the x-intercept or x. So both C and D are not the answer because the y-intercept is not the domain, the y-intercept is the range. Next I looked at both A and B, well, if you look closely answer choice A says "excluding -2 and including 3" and choice B says "including -2 and excluding 3". I also seen on the graph that the point of (3,3) has a filled in dot and the point at (-2,-1) has an opened dot. A filled in dot always means you either have a ≥ (greater than or equal to sign) or a ≤ (less than or equal to sign). While an opened dot always means you just have < (greater than) or a > (less than) sign. So the correct answer is A!! Hope you have a fantastic rest of your day! :)))
Answer:
the answer is the first one I think but I'm pretty sure
If you have a decimal you would move it to the right two numbers like .56 to 56. percent or you have a fraction you would put a decimal like 4/5 to 4/5.= 80.percent.
