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tatyana61 [14]
3 years ago
8

What is the GCF of the polynomial: −16y^4+12y^2−4y?

Mathematics
2 answers:
Tju [1.3M]3 years ago
6 0

Answer:

4y

Step-by-step explanation:

16 12 4 ---- all could be divided by 4

4   3   1 ---- no more common factors

GCF = 4y --- there are 3 y's in the problem, find the one with the smallest power and use it and the smallest power in this case is y^1

Nana76 [90]3 years ago
3 0

Answer:

4y

Step-by-step explanation:

every part of the equation can be evenly divided by 4 and y

so this leaves you with 4y (-4y^{3} + 3y - 1)

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PLEASE ANSWER PLZZZ HELP
stich3 [128]
0.0307 or what are you giving us here?
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3 years ago
What is -3x-32=-2(5-4x)
san4es73 [151]

Answer:

x=−2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−3x−32=−2(5−4x)

−3x+−32=(−2)(5)+(−2)(−4x)(Distribute)

−3x+−32=−10+8x

−3x−32=8x−10

Step 2: Subtract 8x from both sides.

−3x−32−8x=8x−10−8x

−11x−32=−10

Step 3: Add 32 to both sides.

−11x−32+32=−10+32

−11x=22

Step 4: Divide both sides by -11.

−11x

−11

=

22

−11

5 0
3 years ago
Read 2 more answers
In quadrants 1 and 3 the x-coordinate of a point is positive?
True [87]

no because one is negative and the other is positive so no it didn't

7 0
3 years ago
Mylia has 20.65 m of wire. She used 15.8 m to make a sculpture. She cut the rest of the wire into 3 equal parts. What is the len
deff fn [24]

Answer:

1.6 meters

Step-by-step explanation:

20.65-15.8=4.85

4.85/3=1.6

5 0
2 years ago
A major department store chain is interested in estimating the mean amount its credit card customers spent on their first visit
sergiy2304 [10]

Answer:

95% Confidence interval: (39.43, 61.58)

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = $50.50

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation = 20

95% Confidence interval:

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 14 and}~\alpha_{0.05} = \pm 2.1447  

=50.50 \pm 2.1447(\dfrac{20}{\sqrt{15}} ) \\\\= 50.50 \pm 11.0751 \\= (39.4249,61.5751)\\\approx (39.43, 61.58)  

95% Confidence interval: (39.43, 61.58)

8 0
3 years ago
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