13+3k=11
-Move constant to the right-hand side and change its sign
3k=11-13
Calculate the difference
3k=-2
Divide both sides by 3
K= -2/3
Answer:
A) 0.303
The probability that a randomly selected student from the class has brown eyes , given they are male
![P(\frac{B}{M} ) = 0.3030](https://tex.z-dn.net/?f=P%28%5Cfrac%7BB%7D%7BM%7D%20%29%20%3D%200.3030)
Step-by-step explanation:
<u>Explanation</u>:-
Given data
Brown Blue Hazel Green
Females 13 4 6 9
Males 10 2 9 12
<em>Let 'B' be the event of brown eyes </em>
<em>Total number of males n(M) = 33</em>
Let B/M be the event of randomly selected student from the class has brown eyes given they are male
<em>The probability that a randomly selected student from the class has brown eyes , given they are male</em>
<em></em>
<em></em>
<em>From table the brown eyes from males = 10</em>
![P(\frac{B}{M} ) = \frac{10}{33}](https://tex.z-dn.net/?f=P%28%5Cfrac%7BB%7D%7BM%7D%20%29%20%3D%20%5Cfrac%7B10%7D%7B33%7D)
![P(\frac{B}{M} ) = 0.3030](https://tex.z-dn.net/?f=P%28%5Cfrac%7BB%7D%7BM%7D%20%29%20%3D%200.3030)
<u>Final answer</u>:-
The probability that a randomly selected student from the class has brown eyes , given they are male
![P(\frac{B}{M} ) = 0.3030](https://tex.z-dn.net/?f=P%28%5Cfrac%7BB%7D%7BM%7D%20%29%20%3D%200.3030)
Answer: B. 500
Step-by-step explanation:
Ask for details Follow Report by Anchorman 1 hour ago
Answers
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Ahh yes, negative exponents always give us a scare once and a while. All the negative means is to flip the position of its base. For instance, if x has a negative exponent and x in the denominator, all you would have to do is move x to the numerator with the same power (except it's no longer negative). Before we substitute x and all the other variables which the values given, let's eliminate the negatives first.
After flipping positions/eliminating the negative exponents it should look like this:
![\frac{ 2^{2} x^{3} }{ y^{5} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%202%5E%7B2%7D%20x%5E%7B3%7D%20%7D%7B%20y%5E%7B5%7D%20%7D%20)
which simplifies to
![\frac{ 4 x^{3} }{ y^{5} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%204%20x%5E%7B3%7D%20%7D%7B%20y%5E%7B5%7D%20%7D%20)
now that everything is simplified, and all negative exponents are eliminated we can substitute x with 2, and y with (-4).
![\frac{4 (2)^{3} }{ (-4)^{5} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%20%282%29%5E%7B3%7D%20%7D%7B%20%28-4%29%5E%7B5%7D%20%7D%20)
which simplifies to
![\frac{4(8)}{(-1024)} = \frac{32}{-1024} = - \frac{1}{32}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%288%29%7D%7B%28-1024%29%7D%20%3D%20%5Cfrac%7B32%7D%7B-1024%7D%20%3D%20-%20%5Cfrac%7B1%7D%7B32%7D%20)
Final Answer: - \frac{1}{32} [/tex]
Answer:
![12 \sqrt{2}](https://tex.z-dn.net/?f=12%20%5Csqrt%7B2%7D%20)
Step-by-step explanation:
Taking the terms one at a time,
![\frac{14}{ \sqrt{2} } \\ \frac{14 * \sqrt{2} }{ \sqrt{2} * \sqrt{2} } \\ \frac{14 \sqrt{2} }{2} \\ 7 \sqrt{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B14%7D%7B%20%5Csqrt%7B2%7D%20%7D%20%20%5C%5C%20%20%20%5Cfrac%7B14%20%2A%20%20%5Csqrt%7B2%7D%20%7D%7B%20%5Csqrt%7B2%7D%20%2A%20%20%5Csqrt%7B2%7D%20%20%7D%20%20%5C%5C%20%20%20%5Cfrac%7B14%20%20%5Csqrt%7B2%7D%20%7D%7B2%7D%20%20%5C%5C%20%207%20%5Csqrt%7B2%7D%20%20)
![\sqrt{50} \\ \sqrt{25 * 2} \\ \sqrt{25}* \sqrt{2} \\ 5 * \sqrt{2} \\ 5 \sqrt{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B50%7D%20%5C%5C%20%20%5Csqrt%7B25%20%2A%202%7D%20%5C%5C%20%20%5Csqrt%7B25%7D%2A%20%20%5Csqrt%7B2%7D%20%20%20%20%5C%5C%205%20%2A%20%20%5Csqrt%7B2%7D%20%20%20%5C%5C%205%20%5Csqrt%7B2%7D%20)
Adding the terms, you have;
![7 \sqrt{2} + 5 \sqrt{2} =(7 + 5) \sqrt{2} = 12 \sqrt{2}](https://tex.z-dn.net/?f=7%20%5Csqrt%7B2%7D%20%2B%205%20%5Csqrt%7B2%7D%20%3D%287%20%2B%205%29%20%5Csqrt%7B2%7D%20%3D%2012%20%5Csqrt%7B2%7D%20%20%20%20)
Hope it helps!
I'm out!