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3 years ago

WILL GIVE BRAINLIEST IF POSSIBLE IF YOU ANSWER CORRECTLY AND WITH ALL STEPS

Mathematics

2 answers:

Aneli [31]3 years ago

5 0

Answer:

Step-by-step explanation:

Each figure adds four boxes to the bottom.

(1) The preceding figure, figure zero would have no rows of four and would thus just have two boxes.

(2) Each figure adds four boxes and started with two so

y(x)=4x+2

(3)

y(22)=4(22)+2

y(22)=88+2=90

taurus [48]3 years ago

3 0

Answer:

Step-by-step explanation:

iasss

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The following is an equilateral triangle. Solve for y.

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Answer:

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3 years ago

The half-life is a substance is 375 years. If 70 grams is present now, how much will be present in 500 years?

Lynna [10]

Answer:

27.76 grams will be present in 500 years

Step-by-step explanation:

The given formula is $A=A_{o}e^{kt}$ , where A is the value of the substance in t years, and $A_{o}$ is the initial value

∵ The half-life is a substance is 375 years

- Substitute A by $\frac{1}{2}A_{o}$ and t by 375 to find the value of k

∴ $\frac{1}{2}A_{o}=A_{o}e^{375k}$

- Divide both sides by $A_{o}$

∴ $\frac{1}{2}=e^{375k}$

- Insert ㏑ in both sides

∴ ㏑( $\frac{1}{2}$ ) = ㏑ ( $e^{375k}$ )

- Remember ㏑ ( $e^{n}$ ) = n

∵ ㏑ ( $e^{375k}$ ) = 375 k

∴ ㏑( $\frac{1}{2}$ ) = 375 k

- Divide both sides by 375

∴ k ≈ -0.00185

∴ $A=A_{o}e^{-0.00185t}$

∵ 70 grams is present now

- That means the initial value is 70 grams

∴ $A_{o}$ = 70

∵ The time is 500 years

∴ t = 500

- Substitute the values of $A_{o}$ and t in the formula

∵ $A=70e^{-0.00185(500)}$

∴ A = 27.76

∴ 27.76 grams will be present in 500 years

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3 years ago